Help me simplify this! Steps!
\[\frac{ X+3 }{ \sqrt{x^{2}-9} }\]
both lower case xs
what does "simplify" mean in this case?
get rid of the square root in the denominator
then multiply top and bottom by \(\sqrt{x^2-9}\)
you will have a term to cancel after you do that
so I got X^4-18X^2+81 for the denominator
no
\[\sqrt{\heartsuit}\times \sqrt{\heartsuit}=\heartsuit\]
denominator is just the term inside the radical
or rather "expression"
You can also think of it as exponents to \[\sqrt{x} = x^{1/2}\] \[\huge x^{1/2} \times x^{1/2} = x^{1/2+1/2} = x \]
got it!
then factor the difference of two squares you get in the denominator, then cancel with the common factor in the numerator
\[\frac{ \sqrt{X^2-9} }{ x-3 }\]
looks good to me
I get confused when I have to multiply by the opposite side? What instance would you use that? @satellite73
i guess when there is "another side" i take it you mean when you have an equation , rather than an expression
unless you mean when you have to multiply by the "conjugate" as in \[\frac{3}{\sqrt{2}+5}\]
Yup thats what I got confused on!
that expression has a radical and a whole number in the denominator yours in this question only had a radical there
Thanks for the help @satellite73
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