Why is there not an absolute value for b?
one sec
\[\frac{\sqrt{a^2b^{10}}}{\sqrt{b}}\]
This is the problem I need to simplify and the answer is \[\left|a\right|b^4\sqrt{b}\]
Why does the b^4 not have an absolute value? My teacher in class told me the rule even exponents and even exponents with an odd exponent is an absolute value
b^4 cannot be negative and needs no absolute value symbol to indicate that it is. a needs the absolute value symbol because it could be negative.
gotcha
b is undefined for b\(\ge\)0
\(\color{#000000 }{ \displaystyle \frac{ \sqrt{a^2b^{10}} }{\sqrt{~b~}} }\) the absolute value \(z\) is defined as; \(|z|=\sqrt{z^2~}\) (for real number \(z\)) \(\color{#000000 }{ \displaystyle \frac{ \sqrt{a^2b^{10}} }{\sqrt{~b~}} \Rightarrow \frac{ \sqrt{a^2}\cdot \sqrt{b^{10}} }{\sqrt{~b~}}\Rightarrow \frac{|a|\cdot \sqrt{\left(b^{5}\right)^2} }{\sqrt{~b~}}\Rightarrow\frac{ |a|\cdot |b^5| }{\sqrt{~b~}}}\) then we will rationalize the denominator \(\color{#000000 }{ \displaystyle \frac{ |a|\cdot |b^5|\cdot \sqrt{~b~} }{b} }\) this is what I would be getting, but recalling that b is positive anyway, \(\color{#000000 }{ \displaystyle \frac{ |a|\cdot b^5\cdot \sqrt{~b~} }{b} }\) \(\color{#000000 }{ \displaystyle |a|\cdot b^4\cdot \sqrt{~b~} }\)
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