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Mathematics 18 Online
OpenStudy (diana.xl):

http://prntscr.com/9hkqlk http://prntscr.com/9hkqpn

OpenStudy (diana.xl):

Are these correct?

imqwerty (imqwerty):

yeah both are correct :)

OpenStudy (diana.xl):

Ty

OpenStudy (inkyvoyd):

first one is wrong...

OpenStudy (inkyvoyd):

second one is right...

imqwerty (imqwerty):

oh damn yeah x must be greater than 2

OpenStudy (inkyvoyd):

@imqwerty you gave @Diana.xL the wrong answer for the first question

imqwerty (imqwerty):

yea sorry for that but its not always decreasing as for x<2 the value of y goes on increasing

OpenStudy (inkyvoyd):

The function is always decreasing. We are looking at a hyperbola with vertex at point (2,2) so the equation is y=1/(x-2)+2 dy/dx = -1/(x-2)^2 note that we have the NEGATIVE of a square here so the slope is ALWAYS negative. Ergo, the function is ALWAYS decreasing.

OpenStudy (inkyvoyd):

of course at x=2 the function is undefined but beyond that hte function is decreasing at x>2 and x<2 which excludes 2 anyways

imqwerty (imqwerty):

yeah i get your point but generally in such ques for example like we say x<2 it means that as we go away from x=2 ...the value of y keeps increasing

imqwerty (imqwerty):

away from x=2 in the negative direction

OpenStudy (inkyvoyd):

no. The function is always decreasing because whenever you go towards the right, the value of the function decreases. If you move in the negative direction, and the function goes DOWN, then the function increases. But your function is going UP in the NEGATIVE direction, implying the function DECREASES.|dw:1450865572097:dw| This function always decreases. Move left and f(x) goes up. move right and f(x) goes down.

OpenStudy (inkyvoyd):

I don't know what you're talking about...

imqwerty (imqwerty):

|dw:1450865643665:dw|

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