Question

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.
A)h=0,5cos(3.14/12 t)+9.5 B)h=0,5cos(3.14/6t)+9.5 C)h=cos(3.14/12 t)+9 D)h=cos(3.14/6 t)+9

Answer 1

fix the question

Answer 2

*fixed?

Answer 3

yes

Answer 4

I see now

Answer 5

i dont understand

Answer 6

which formula would i use

Answer 7

you can use the formula for general trig sinusoidal function

Answer 8

y = a * cos( 2pi / period( x - P.S.) + midline

Answer 9

y = 0.5 * cos( 2pi / 12 ( t - P.S.)) + 9.5
the phase shift is 0,
so the answer is b)
y = 0.5 cos (pi/6 *t ) + 9.5

Answer 10

here is an animation of the problem
https://www.desmos.com/calculator/93dhjrr3ol
move the slider
the dot represents the height of the hour hand