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OpenStudy (anonymous):
You went from 13/3 to 13/5
RhondaSommer (rhondasommer):
how do you get area @LegendarySadist
OpenStudy (anonymous):
\[\large \sf A=l \times w\]
OpenStudy (anonymous):
length, not height
RhondaSommer (rhondasommer):
sorry, simple mistake :)
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RhondaSommer (rhondasommer):
multiply width times length
OpenStudy (anonymous):
For this kind of multiplication I prefer the foil method. \[\large \sf (4+\frac{1}{3})(5+\frac{1}{5})=(4\times 5)+(4 \times \frac{1}{5})+(\frac{1}{3} \times 5)+(\frac{1}{3} \times \frac{1}{5})\]
RhondaSommer (rhondasommer):
that could work too!
RhondaSommer (rhondasommer):
something more simple that you could do is \[4*5 . and . 1/3*1/5 add . them . together :)\]
OpenStudy (anonymous):
That wouldn't work.
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RhondaSommer (rhondasommer):
your right sorry...dont know what i was typing lol
RhondaSommer (rhondasommer):
what you like to do would work best...I was thinking of a different type of math.