In a a parallelogram DEFG, DH=y+3, HF=2x+1, GH=2y-1, and HE=x+4 what are values of y and x
I'll give medal!!
Hi Welcome To Openstudy :-) Any ideas on where to start?
No:(
It's alright ^_^ Ok so we can say H is the center of both parallelogram diagonals
Yes
ok so we have this: DH = HF \[\huge~\rm~y+3=2x+1\] isolate y
X=y/2+1?
Yes we can also write it as x=1/2y+1 <---leave it as this for right now Next we know the GH=HE So... \[\huge~\rm~ 2y-1=x-4\] isolate the y
Y=x/2-3/2
I think x =3 and y =4
Wait no
sorry isolate the 2nd equation for x
not y
X=2y+3
Good now we have 2 equations x=1/2y+1 X=2y+3 Now we use substitution form here think you can do it? :)
Wait what are your answer choices?
X=14 and y=11, x=3 and y = 4, and x=7 and y. =4, x=1 and y =. 11
This? |dw:1450899721682:dw|
Not the same question
Ok anyways... Good now we have 2 equations x=1/2y+1 X=2y+3 Now we use substitution form here think you can do it? :)
We isolated wrong y+3=2x+1 <---this is what we are supposed to have
x=2y-5 and x=(y+2)/2 would be our 2 equations
Oh yeah
Now try solving :)
X = 3 and y=4
Can you show me how you got that?
I substituted, 3=2(4)-5 and 3=4+2/2
nice :)
Perfect :)
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Thanks ! Happy holidays
Same to you! :D and yw ^_^
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