Question

what are the zero(s) of the function

Answer 1

The zeros of a function f are found by solving the equation f(x) = 0.

Answer 2

\[f(x)=\frac{ 4x^2-36x }{ x-9 }\]\[0=\frac{ 4x^2-36x }{ x-9 }\]

Answer 3

so its -9?

Answer 4

nope
since that the highest coefficent for x is power of 2,it must hv two values for x\[0=\frac{ 4x\color{red}{^2}-36x }{ x-9 }\]

Answer 5

so it would be 0 and 9 but why

Answer 6

Step 1 : Multiply both sides by x-9\[0\times\color{red}{x-9}=\frac{ 4x^2-36x }{ x-9 }\times\color{red}{x-9}\]

Answer 7

\[0=4x^2-36x\]

Answer 8

right right

Answer 9

Step 2 : Factorise the expression\[4x^2-36x=0\]\[4x(x-9)=0\]

Answer 10

Step 3 :Solve for x\[4x=0~or~x-9=0\]

Answer 11

Example: Let's solve the 2nd equation for x.
Add 9 to both sides of the equation.
Simplify.
x=??

Answer 12

oh okay thank you were a big help marc and thank mathmale too

Answer 13

do you think you could help me with more problems like this ?

Answer 14

welcome ^_^

Answer 15

sure

Answer 16

ok ill open a new question

Answer 17

ok

Answer 18

Sorry for late reply, but the function is undefined at \(x=9\), since the denominator is \(x-9\).

Answer 19

So, \(x=9\) can not be the zero ... (since that isn't not even a point on the function).