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Mathematics 13 Online
rebeccaxhawaii (rebeccaxhawaii):

medal

rebeccaxhawaii (rebeccaxhawaii):

OpenStudy (anonymous):

Hi, Do you know that you CANNOT divide any number by ZERO?

rebeccaxhawaii (rebeccaxhawaii):

yes

OpenStudy (anonymous):

good! so in any fraction the denominator cannot become zero. Ok?

rebeccaxhawaii (rebeccaxhawaii):

ok

OpenStudy (anonymous):

So, in your fraction, could you tell me what is the denominator?

rebeccaxhawaii (rebeccaxhawaii):

x+4

OpenStudy (anonymous):

very good. For which amount of X it will become Zero?

rebeccaxhawaii (rebeccaxhawaii):

-4

OpenStudy (anonymous):

Nice. This is the discontinuity point of your function. You got it?

rebeccaxhawaii (rebeccaxhawaii):

so thats for x but we plug x in to find y ?

OpenStudy (anonymous):

No! You say X=-4 is the discontinuity point of this function. Ok?

rebeccaxhawaii (rebeccaxhawaii):

yeah but (-4, ? ) what is y

OpenStudy (anonymous):

Y will be INFINITY. that's exactly why it is the discontinuity point. Do you have a calculator?

rebeccaxhawaii (rebeccaxhawaii):

my y is an exact number so it cant be infinity

OpenStudy (anonymous):

No. Use a calculator to see what will happen if you get so close to X=-4 for example, substitute X=-3.95 now. I'm waiting to see what Y will be.

rebeccaxhawaii (rebeccaxhawaii):

wait what do you want me to plug into the calculator

OpenStudy (anonymous):

calculate your fraction for these three numbers: X=-3.95 X=-3.99 X=-3.9999

rebeccaxhawaii (rebeccaxhawaii):

wait im lost why cant we just use -4

OpenStudy (anonymous):

because your calculator gives you an error

OpenStudy (solomonzelman):

yavar, actually there is X+4 on the to as well, so the idea of the limit would tell us that the function is just 2x-3, which correct, but correct only for \(x\ne-4\).

OpenStudy (solomonzelman):

on the "top" too (correction, grammar)

OpenStudy (anonymous):

yes, she doesn't have any idea why X=-4 is discontinuity point.

OpenStudy (solomonzelman):

I mean, f(x)=(2x-3)(x+4) /(x+4) (after factoring) So, limit x->4\(^{\pm}\)f(x) = 2x-3

OpenStudy (solomonzelman):

I am saying that plugging -3.95 into the function doesn;t work, unles you mean just plugging into the bottom

rebeccaxhawaii (rebeccaxhawaii):

no i do know why x=-4 but i need to figure out what y is

OpenStudy (solomonzelman):

didn't mean to distract, apologize...

OpenStudy (anonymous):

I checked it before but didn't get those factors. I need to sleep. !!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (solomonzelman):

for better idea of discountiuity, it would be better to look at g(x)=1/(x+4)

OpenStudy (solomonzelman):

(( And by the way, I think she is asking what y of the function would have been, if the function was continuous.... ))

OpenStudy (anonymous):

Yes! Revecca! IT IS 6:10 AM HERE and I've been working for more than 16 hours. I am so sorry I gave you a wrong answer. I'm sure @SolomonZelman gives you better advice. Sorry again and Do great!

OpenStudy (solomonzelman):

The discontinuity point, is the point where the function is not connected. (one way to interpet "discountimnuity")

rebeccaxhawaii (rebeccaxhawaii):

thanks for your help though @Yavar

OpenStudy (solomonzelman):

For example, I want to figure out the point of discountinuity of; \(\color{#000000 }{ \displaystyle f(x)=\frac{(7x+6)(x-5)}{x-5} }\). I know the function is undefined for x=5, (because then the denominator =0) So, we can cancel out (x-5) on top and bottom, and we shall keep in mind the fact that the function does not have a point at x=5. (when canceling x+5 on top and bottom) \(\color{#000000 }{ \displaystyle f(x)=7x+6}\) And \(\color{#000000 }{ \displaystyle f(5)=7(5)+6=35+6=41}\) So we know that the point of discountinuity is (5,41)....

rebeccaxhawaii (rebeccaxhawaii):

but with my problem there is no perfect binomial to split it up into

OpenStudy (solomonzelman):

\(2x^2+5x-12=(2x-3)(x+4) \)

OpenStudy (solomonzelman):

So, in your case the function is \(\color{#000000 }{ \displaystyle f(x)=\frac{(2x-3)(x+4)}{x+4} }\). and you need to determine the point of discountinuity.

rebeccaxhawaii (rebeccaxhawaii):

-3+4 doesnt equal 5

OpenStudy (solomonzelman):

???

OpenStudy (solomonzelman):

I don't really understand where -3+4 is coming from

OpenStudy (solomonzelman):

but, -3+4•2=5

OpenStudy (solomonzelman):

and the factoring is correct....

rebeccaxhawaii (rebeccaxhawaii):

ohhhhhhhhhhhhhhhhhhhhhhh i see thanks

rebeccaxhawaii (rebeccaxhawaii):

thats why it has been so confusing you need to multiply that number by it

OpenStudy (solomonzelman):

Ok, you want to determine the discontinuity point of \(\color{#000000 }{ \displaystyle f(x)=\frac{(2x-3)(x+4)}{x+4} }\). And, as you said the function is not continuous at x=-4, So once you know noted that x\(\ne\)-4, you can cancel the (x+4)'s out, and to then evaluate the function at x=-4, to find the y-coordinate of this point of discountinuity (once you have already known that the x-coordinate of point of discountinuity is =-4).

rebeccaxhawaii (rebeccaxhawaii):

ok then to figure out what y is you plug -4 into the finished product which is (2x-3) so 2x(-4)-3 giving you -11 so your discontinuity is at (-4, -11)

OpenStudy (solomonzelman):

yes, the point of discountinuity is (-4,-11). Fabulous!

rebeccaxhawaii (rebeccaxhawaii):

yayyyy but now i have to find the zeros

OpenStudy (solomonzelman):

the zeros, (or the x intercepts)...

rebeccaxhawaii (rebeccaxhawaii):

i have to find what the zeros of the function are

OpenStudy (solomonzelman):

when you are finding the zeros, you are actually going to have to cancel (x+4)'s on top and bottom , i.e. to deal with f(x)=2x-3 At what value(s) of x, is f(x) going to be equal to 0?

rebeccaxhawaii (rebeccaxhawaii):

-3/2

rebeccaxhawaii (rebeccaxhawaii):

but i need to find the other zero bc there is 2

OpenStudy (solomonzelman):

Actually, there is only 1 zero, because at x=-4, the function does NOT have an x-intercept.

OpenStudy (solomonzelman):

you found the zero incorrectly. x=-3/2 is not the "zero"

rebeccaxhawaii (rebeccaxhawaii):

where is the zero at

OpenStudy (solomonzelman):

f(x)=2x-3 0=2x-3 x=?

rebeccaxhawaii (rebeccaxhawaii):

x=3/2 @SolomonZelman

OpenStudy (solomonzelman):

yes

OpenStudy (solomonzelman):

(and that is the only zero there is to the function)

rebeccaxhawaii (rebeccaxhawaii):

rebeccaxhawaii (rebeccaxhawaii):

i dont understand why y is 0

OpenStudy (solomonzelman):

f(3/2)=2(3/2)-3=3-3=0

rebeccaxhawaii (rebeccaxhawaii):

ohok thank you for navigating through my cluelessness, you helped a lot

OpenStudy (solomonzelman):

yw

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