medal
Hi, Do you know that you CANNOT divide any number by ZERO?
yes
good! so in any fraction the denominator cannot become zero. Ok?
ok
So, in your fraction, could you tell me what is the denominator?
x+4
very good. For which amount of X it will become Zero?
-4
Nice. This is the discontinuity point of your function. You got it?
so thats for x but we plug x in to find y ?
No! You say X=-4 is the discontinuity point of this function. Ok?
yeah but (-4, ? ) what is y
Y will be INFINITY. that's exactly why it is the discontinuity point. Do you have a calculator?
my y is an exact number so it cant be infinity
No. Use a calculator to see what will happen if you get so close to X=-4 for example, substitute X=-3.95 now. I'm waiting to see what Y will be.
wait what do you want me to plug into the calculator
calculate your fraction for these three numbers: X=-3.95 X=-3.99 X=-3.9999
wait im lost why cant we just use -4
because your calculator gives you an error
yavar, actually there is X+4 on the to as well, so the idea of the limit would tell us that the function is just 2x-3, which correct, but correct only for \(x\ne-4\).
on the "top" too (correction, grammar)
yes, she doesn't have any idea why X=-4 is discontinuity point.
I mean, f(x)=(2x-3)(x+4) /(x+4) (after factoring) So, limit x->4\(^{\pm}\)f(x) = 2x-3
I am saying that plugging -3.95 into the function doesn;t work, unles you mean just plugging into the bottom
no i do know why x=-4 but i need to figure out what y is
didn't mean to distract, apologize...
I checked it before but didn't get those factors. I need to sleep. !!!!!!!!!!!!!!!!!!!!!!!
for better idea of discountiuity, it would be better to look at g(x)=1/(x+4)
(( And by the way, I think she is asking what y of the function would have been, if the function was continuous.... ))
Yes! Revecca! IT IS 6:10 AM HERE and I've been working for more than 16 hours. I am so sorry I gave you a wrong answer. I'm sure @SolomonZelman gives you better advice. Sorry again and Do great!
The discontinuity point, is the point where the function is not connected. (one way to interpet "discountimnuity")
thanks for your help though @Yavar
For example, I want to figure out the point of discountinuity of; \(\color{#000000 }{ \displaystyle f(x)=\frac{(7x+6)(x-5)}{x-5} }\). I know the function is undefined for x=5, (because then the denominator =0) So, we can cancel out (x-5) on top and bottom, and we shall keep in mind the fact that the function does not have a point at x=5. (when canceling x+5 on top and bottom) \(\color{#000000 }{ \displaystyle f(x)=7x+6}\) And \(\color{#000000 }{ \displaystyle f(5)=7(5)+6=35+6=41}\) So we know that the point of discountinuity is (5,41)....
but with my problem there is no perfect binomial to split it up into
\(2x^2+5x-12=(2x-3)(x+4) \)
So, in your case the function is \(\color{#000000 }{ \displaystyle f(x)=\frac{(2x-3)(x+4)}{x+4} }\). and you need to determine the point of discountinuity.
-3+4 doesnt equal 5
???
I don't really understand where -3+4 is coming from
but, -3+4•2=5
and the factoring is correct....
ohhhhhhhhhhhhhhhhhhhhhhh i see thanks
thats why it has been so confusing you need to multiply that number by it
Ok, you want to determine the discontinuity point of \(\color{#000000 }{ \displaystyle f(x)=\frac{(2x-3)(x+4)}{x+4} }\). And, as you said the function is not continuous at x=-4, So once you know noted that x\(\ne\)-4, you can cancel the (x+4)'s out, and to then evaluate the function at x=-4, to find the y-coordinate of this point of discountinuity (once you have already known that the x-coordinate of point of discountinuity is =-4).
ok then to figure out what y is you plug -4 into the finished product which is (2x-3) so 2x(-4)-3 giving you -11 so your discontinuity is at (-4, -11)
yes, the point of discountinuity is (-4,-11). Fabulous!
yayyyy but now i have to find the zeros
the zeros, (or the x intercepts)...
i have to find what the zeros of the function are
when you are finding the zeros, you are actually going to have to cancel (x+4)'s on top and bottom , i.e. to deal with f(x)=2x-3 At what value(s) of x, is f(x) going to be equal to 0?
-3/2
but i need to find the other zero bc there is 2
Actually, there is only 1 zero, because at x=-4, the function does NOT have an x-intercept.
you found the zero incorrectly. x=-3/2 is not the "zero"
where is the zero at
f(x)=2x-3 0=2x-3 x=?
x=3/2 @SolomonZelman
yes
(and that is the only zero there is to the function)
i dont understand why y is 0
f(3/2)=2(3/2)-3=3-3=0
ohok thank you for navigating through my cluelessness, you helped a lot
yw
Join our real-time social learning platform and learn together with your friends!