Let f(x) = sin^10(x) − cos(x), 0 <= x<=pi . Show that there is a solution of f(x) = 0 in (0,pi ) please help
the function \(f(x)\) is continuous inside all the real line, furthermore, we have: \(f(0)=-1\), and \(f(\pi)=1\) so what can you conclude?
I did this, but I didn't how to complete the answer... please, can you just explain to me.. it may come in the final test
such \(continuous\) function takes all values inside the set \([-1,1]\), so there exists, inside the interval \([0, \pi]\), at least one point \(x_0\), such that: \(f(x_0)=0\)
since such function have to go in a \(continuous\) way, from negative values to positive values
So, what is the point,that will lead the equation to be zero??? please help
the point is that the function is continuous, so, it has to take all values between \(-1<0\) and \(1>0\), hence , such function will be equal to zero at least one time inside \([0,\pi]\)
thank yooooooooooooooooooooooou so much,,, I got it.......
the continuity is the key property
:)
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