Help!! I don't know how to do this The endpoints of AB are A(2, 3) and B(8, 1). The perpendicular bisector of AB is CD, and point C lies on AB. The length of CD is (root of 10) units. The coordinates of point C are (-6, 2) (5, 2) (6, -2) (10, 4) . The slope of is -3 -1/3 1/3 3 . The possible coordinates of point D are (4, 5) (5, 5) (6, 5) (8, 3) and (2, 1) (4, -1) (5, -1) (6, -1) . Please pick 1 answer for all the questions
Could you tell me what you're exactly looking for? The coordinate of C and the slope of the perpendicular bisector?
@pooohbear99
@yavar The coordinates of point C,The slope of CD,& The possible coordinates of point D(need 2)
since CD is perpendicular bisector one point is mid point of A and B
mid point is ((x1+x2)/2,(y1+y2)/2)
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!) A(2,3) ,B(8,3) COORDINATES OF POINT C \[C =(\frac{ x1+x2 }{ 2 },\frac{ y1+y2 }{ 2 })\]
\[C =(\frac{ 2+8 }{ 2 },\frac{ 3+3 }{ 2 })\] find C=
C =(5.3)
i mistaken B(8,1) then C = (5,2)
if u are following i can continue
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