Question

Find the tangent line equation for the following at (-2,-2):

Answer 1

\[4x^2+2y^2-10=3xy-x\]

Answer 2

I tried solving this out and I got the following: \[\frac{ dy }{ dx } = \frac{ 8x - 3y }{ 3x + 4y } + 1\]

Answer 3

I'm not sure if I skipped a step or just didn't derive everything properly.

Answer 4

Answer choices are:
a) -2x - 9y = 22
b) 9x + 2y = -22
c) 9x + 2y = 12
d) 2x - 9y = 14
e) -9x + 2y = -22

Answer 5

8x + 4*y*y' = 3x*y' + 3y - 1

(3x - 4y)* y' = 8x - 3y + 1

\[y' = \frac{ 8x - 3y +1 }{ 3x - 4y }\]

Answer 6

slope -9/2 at point (-2,-2)

Answer 7

and having the slope and a point you can derive the line equation.