A rectangle has a width of 2x-3 and a length of 3x+1 a) Write its area as a simplified polynomial b) Write expressions for the dimensions if the width is doubled and the length is increased by 2 c) Write the new area as a simplified polynomial
Where are you having issues with this problem?
@LifeEngineer I don't know what to do
What is the formula for the area of a triangle
*rectangle
base times height
Area = Length times Width
So multiply the length, by the width
Whoops! Yea, length times width is what I meant to say
(2x-3)(3x+1) like that?
yes now foil this
Length = 3x+1 Width = 2x-3 Area = (2x-3)(3x+1) FOIL First, Outer, Inner, Last First = \[2x \times 3x\] First = 6x Outer = \[2x \times 1 \] Outer = 2x Inner = \[-3 \times 3x\] Inner = -9x Last = -3 x 1 Last = -3
So now we add them all up First is actually 6x^2
\[6x^2 + 2x - 9x - 3\] What do we get?
(2x-3)(3x+1) =6x^2+2x-9-3 =6x^2+2x-12
thatʻs not right
Itʻs -9x , not -9
(2x-3)(3x+1) =6x^2+2x-9x-3 =6x^2-7x-3
Correct
We have solved a)
Is that the area?
Yes
Does that mean that I have to put cm^2 at the end of it?
If that is the unit of measure, then yes
Now b) Write expressions for the dimensions if the width is doubled and the length is increased by 2 Width = 2x-3 Length = 3x+1 Doubled is multiplication We basically multiply 2x-3 by itself This is represented by... (2x - 3)^2 which is basically (2x - 3)(2x - 3) So we foil again
Can you try do that one?
(2x-3)(2x-3) =4x^2-6x-6x+9 =4x^2-12x+9
Correct, now that is the doubled form of 2x - 3
Now we just increase 3x+1 by 2
Do you know what "increased by" means?
(3x+1)(3x+1) =9x^2+3x+3x+1 =9x^2+6x+1
No...that is doubling it
We donʻt want to multiply it by itself, we want to do a different operation with the number 2
What does increased by 2 mean? To the power of two?
(3x+1)^2 like that?
no
Let says I have a laser gun. It is currently at power level two. If I increase the power level by 2, what level will it be at?
4 ?
Yes, but what mathematical operation would you do to get there?
addition?
Yes
So 3x + 1 increased by 2
3x+1 turns into.... 5x+3
How did you get that
3x +2 = 5x 1 +2 = 3
No... You canʻt do 3x + 2 Do you know about like terms?
2 does not have the variable x, thus it is not like terms with 3x, and cannot be added or subtracted from each other
They can, however, multiply and divide each other
Yes, I'm familiar with like terms. I'm just confused.
So 3x + 1 increased by 2 What do we get? ^-^
3x times 2 = 6x 1 times 2 = 2
6x+2
noooo We are doing addition!
But you said: "2 does not have the variable x, thus it is not like terms with 3x, and cannot be added or subtracted from each other"
I thought we didn't have to do addition
Exactly BUT increased by = + So 3x + 1 + 2
We donʻt add the 2 to 3x.
So would 3x + 1 + 2 be my final answer or would it be 3x+3 ?
Yes
Okay and what's the new area?
c) Write the new area as a simplified polynomial Our doubled width = 4x^2-12x+9 Our new length = 3x + 3
So we have to multiply those two new dimensions
(4x^2-12x+9)(3x+3) Do I have to foil this?
We cannot FOIL this (4x^2-12x+9)(3x+3) First we start by pulling out like factors 3x + 3 = 3 • (x + 1) or 3(x + 1)
Next, we factor by splitting the middle term
Factoring 4x2 - 12x + 9 The first term is, 4x2 its coefficient is 4 . The middle term is, -12x its coefficient is -12 . The last term, "the constant", is +9 Multiply the coefficient of the first term by the constant 4 • 9 = 36 Find two factors of 36 whose sum equals the coefficient of the middle term, which is -12 . -36 + -1 = -37 -18 + -2 = -20 -12 + -3 = -15 -9 + -4 = -13 -6 + -6 = -12
Rewrite the polynomial splitting the middle term using the two factors found in the above post -6 4x2 - 6x - 6x - 9 Add up the first 2 terms, pulling out like factors 2x • (2x-3) Add up the last 2 terms, pulling out common factors 3 • (2x-3) Add up the four terms of previous step (2x-3) • (2x-3) Which is the desired factorization. We multiply (2x-3)(2x-3) We get = 3 • (2x - 3)2 • (x + 1)
Correction: 3(2x - 3)^2 • (x + 1)
Simplified that is 12x^3 -24x^2 - 9x + 27
That is your new area
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