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Mathematics 18 Online
OpenStudy (anonymous):

Calc. Help please?

OpenStudy (anonymous):

A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t) = (t)In(3t). Find the acceleration of the particle when the velocity is first zero. I guess it's that last part that's really getting me. When I first saw "find the acceleration..." I thought "find the second derivative" and then "find when the first derivative is equal to 0"

OpenStudy (anonymous):

What am I understanding incorrectly?

zepdrix (zepdrix):

Logic sounds correct :) Make a boo boo in your derivative?

OpenStudy (astrophysics):

The second derivative of position is acceleration

OpenStudy (astrophysics):

Ha, yeah as zep mentioned maybe you made a mistake in the derivative, you will have to apply the product rule first

OpenStudy (anonymous):

I didn't get the derivative wrong (wolfram). And my "second thought" isn't one of the answer choices.

OpenStudy (astrophysics):

What is the first derivative?

zepdrix (zepdrix):

t=1/(3e), this what you get for the time?

OpenStudy (anonymous):

for first derivative, ln(3t)+1

OpenStudy (anonymous):

Yes, zep

zepdrix (zepdrix):

And a(t)=3e isn't one of our options? :OO Hmm

OpenStudy (anonymous):

OH! That's what it's asking!

zepdrix (zepdrix):

lol you silly billy >.< darn I just gave it away

OpenStudy (astrophysics):

lol

OpenStudy (anonymous):

Every once in a while, I'll get a question where I otherwise know what to do, it just doesn't compute. Thanks!

zepdrix (zepdrix):

cool c:

OpenStudy (anonymous):

That's why I come here. Thanks!

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