Calc. Help please?
A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t) = (t)In(3t). Find the acceleration of the particle when the velocity is first zero. I guess it's that last part that's really getting me. When I first saw "find the acceleration..." I thought "find the second derivative" and then "find when the first derivative is equal to 0"
What am I understanding incorrectly?
Logic sounds correct :) Make a boo boo in your derivative?
The second derivative of position is acceleration
Ha, yeah as zep mentioned maybe you made a mistake in the derivative, you will have to apply the product rule first
I didn't get the derivative wrong (wolfram). And my "second thought" isn't one of the answer choices.
What is the first derivative?
t=1/(3e), this what you get for the time?
for first derivative, ln(3t)+1
Yes, zep
And a(t)=3e isn't one of our options? :OO Hmm
OH! That's what it's asking!
lol you silly billy >.< darn I just gave it away
lol
Every once in a while, I'll get a question where I otherwise know what to do, it just doesn't compute. Thanks!
cool c:
That's why I come here. Thanks!
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