Question

Find Maclaurin's series of:

ln(tanx)
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What I did:

f(x) = ln(tanx)
f'(x) = sec^2x/tanx
f''(x) = (2sec^2xtan^2x - sec^4x )/tan^2x

P(x) = f(0)+f'(0)x+(f''(0)x^2 )/2! + ......

Answer 1

HI!!

Answer 2

it looks like a good start, but it must me some kind of generalized maclaurin because this one is not defined at \(x=0\)

Answer 3

@misty1212 , "generalized maclaurin" ?

Answer 4

Key question: What is the domain of ln(tan x)? Finding a Maclaurin series involves setting x to what value?