Question

Multiplying Polynomials

Answer 1

If the expansion of \[(x+\frac{ 1 }{ 14 }y)(x-\frac{ 1 }{ 15 }y)\] gives
\[ x ^{2}+axy+by ^{2}\] where A and B are constants, what is \[\frac{ a }{ b }\]

Answer 2

x^2 - 1/15 yx + 1/14yx - (1/15 * 1/14)y^2

x^2 + (-1/15 + 1/14) - (1/15 * 1/14) y^2

a = 1/210 , b= 1/210

a/b = 1

Answer 3

Bad approach considering higher powers.

Answer 4

Can you please use the equation button, cant really understanding that

Answer 5

\[x^2 - \frac{ 1 }{ 15 } xy +\frac{ 1 }{ 14 } xy - (\frac{ 1 }{ 15 } * \frac{ 1 }{ 14 })y^2\]

Answer 6

\[x^2 - \frac{ 1 }{ 210 } xy - \frac{ 1 }{ 210 }y^2\]

Answer 7

Yea, i got that answer ^ But what do we do now?

Answer 8

By comparing the coefficients of the given equation and this one:

a = -1/210 , b = - 1/210
a/b = 1

Answer 9

Isn't it -1?

Answer 10

-/- = +

Answer 11

It is D: i put 1 D: Well that sucks

Answer 12

No, its -1 @rvc

Answer 13

Well, this sucks haha but anyway thanks @TrojanPoem

Answer 14

@rvc , TROLOL.

Answer 15

@jagr2713 , -/- = + xD

Answer 16

Its -1

Answer 17

what @TrojanPoem ?

Answer 18

Well, it says -1 is the answer

Answer 19

yep
it is -1

Answer 20

Yea i think we established that lol :D

Answer 21

see \[x^2+xy(\frac{ 1 }{ 14 }-\frac{ 1 }{ 15 })-\frac{ 1 }{ 15~ X~ 14 }y^2\]

Answer 22

I miscalculated the middle term.

Answer 23

so the second term would be 15-14/(15 X 14)