You really can't tell the difference between strong acids in water, why is this the case? Usually in some solutions you can determine the difference in strength between two acids
(CH3)3N NH3 NaOH HC2H3O2
Which of the solutions above would be the best solvent to distinguish two strong acids?
We can't actually determine relative strength of ACIDS in water because as water in polar molecule and neutral also.When we add acid to water,it actually dissociates into ions . And we can't predict the strength with the help of ions.
For determining relative strength, we use that solution which can react . Like in case we use NaOH, it is a strong base,if we react any acid with it, reaction occurs definitely. But remember neutralisation reaction occurs when salt is produced and salt is produced when we add STRONG ACID to it. And BASIC SALT is produced when we add WEAK ACID to it .
So, NaOH is likely to determine RELATIVE ACIDIC STRENGTH
Hope you understand and you have any doubts regarding this, please let me know. @greatlife44
I guess it makes sense because strong acids have a tendency to completely dissociate so a solution like water would most likely pick up all the protons and there wouldn't be any difference
I am however wondering about this compound ch3cooh
i think my book says this is the CH3COOH is the answer not sure why though I'll have to get back to this i'm trying to think why this would/wouldnt be the answer. We have a weak acid which partially dissociates, so it doesn't want to give up its proton that much. Say if we had something like this: CH3COOH + H2SO4
how would weak acid reacts with strong acid !
Yup,they can react too only in special case i.e TITRATION
but we are not considering this situation
I need to look at the answer again I don't have my book but I don't how this could be possible.
our aim is to determine relative strength of acids
But how would this work though? even in the titration like they are both acids.
yep ! please re-check your answer again :)
I will get back to you!
:D
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