Question

Please help will fan and medal!

Question in comments.

Answer 1

this one is a little more abstract than the others \[f\circ g(x)=f(g(x))\] then work from the inside out

Answer 2

@satellite73 hi @pooja195 said u could help me

Answer 3

\[f(g(x))=f(x^3)\] since \(g(x)=x^3\)

Answer 4

then since \[f(\spadesuit)=\spadesuit^2-6\spadesuit\] you have \[f(x^3)=(x^3)^2-+x^3\]

Answer 5

oops i made a type \[f(g(x))=f(x^3)=(x^3)^2-6x^3\]

Answer 6

you can clean it up a little since \((x^3)^2=x^6\)

Answer 7

So the bottom right? ._.,

Answer 8

final answer \[x^6-6x^3\]

Answer 9

Thank you. The next one will be 5 out of ten so 5 or 4 more depending on how you look at it