Write a balanced net ionic equation for the following reaction.
BaCl2 (aq) + H2SO4 (aq) --> BaSO4(s) + HCl(aq) Please help show me how to do this. Thanks!
@Rushwr
Start by balancing the reaction given.
Then break up each of the aqueous compounds into their respective aqueous ions. For example and this may be unbalanced BaCl2(aq) breaks up into Ba^2+ and 2 Cl^-. To create the net ionic equation you need to cross out the aqueous ions that appear on both the reactant and product side of the equation. This will result in your balanced net ionic equation.
hint: please note that at left side we have two atoms of hydrogen, so we also have to require two atoms of hydrogen at the right side. Furthermore, we have two atoms of chlorine at the left side, so we have to have two atoms of chlorine at the right side
Okay so first I balance it. Like this? BaCl2 (aq) + H2SO4 (aq) --> BaSO4(s) + 2HCl(aq) I am confused about how to break the aqueous compounds into their respective aqueous ions.
Like this Ba^2+(aq) + 2 Cl^-1(aq) + 2H^+1(aq) + SO4^-2(aq) ---> BaSO4(s) + 2H^+1(aq) + 2Cl^-1(aq). BaSO4 is left how it is as it is a solid in the solution. Cross out ions that appear on both the reactant and product side of the expression.
How did you do that? and Ba^2+(aq) + SO4^-2(aq) --> BaSO4(s)
For example. We know BaCl2 is in aqueous solution therefore it will dissociate into its respective ions which are Ba^2+ and 2Cl^-1. You just break apart each molecule that you know dissociates into aqueous solution. You leave the solid precipitates how they are as they do not dissociate. @toloaf
Ah, alright. I think I get it now. Thank you so much for helping me understand @sweetburger ! =)
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