Question

Algebra Questions- I really need help....

2. Simplify the radical expression
square root 72x^2
A) 36 square root x^2
B) 6x square root 2
C) x square root 36
D) 6 square root 2x^2

3. Simplify the radical expression.
square root 150x^3k^4
A) 75xk^2
B) 5xk square root 6xk
C) 5xk^2 square root 6x
D) 5 square root 6x^3k^4

Answer 1

For 2:\[\sqrt{72x ^{2}}\] Can you put 72 into prime factor form? As in, break it down into multiplication of all prime numbers.

Answer 2

@Alphabet_Sam Factors of 72: 1,2,3,4,6,8,9,12,18,24,36,72

Answer 3

\[\sqrt{72}=\sqrt{8}\sqrt{9}\]

Answer 4

\[6x \sqrt{2}\]

Answer 5

Square root 8: 2.8
Square root 9: 3
@SkepticGod

Answer 6

you cant squartroot 8 because then decimal so keep it like above i did

Answer 7

@SkepticGod Oh okay, can you help me with a few more please

Answer 8

2. sqrt72x^2 = sqrt(36*2*x^2) = sqrt(6^2*2*x^2) = ?
the perfect squares take out from squarroot so than what will get ?

Answer 9

sure so for problem#3 the same concept. break down large number into smaller number that you could squareroot without getting decimal

Answer 10

@Answers101 so do you understand it why are in this way ?

Answer 11

Yes

Answer 12

\[\sqrt{150}=\sqrt{25}\sqrt{6}\]

Answer 13

since x is cube you can divide like this \[\sqrt{x^3}=\sqrt{x^2}\sqrt{x}\]

Answer 14

same thing for k^4
\[\sqrt{k^4}=\sqrt{k^2}\sqrt{k^2}\]

Answer 15

@Answers101 what do you think the answer is?

Answer 16

ops nevermind too late typing