Question

Solve:
F(20) = 100 ^ n + 1000
F(20) = 1000 * 1.1^n

Answer 1

I don't quite understand the given statement and what has to be solved.

Answer 2

Belinda wants to invest in an option that would help to increase her investment value by the greatest amount in 20 years. Will there be any significant difference in the value of Belinda's investment after 20 years if she uses option 2 over option 1?

Answer 3

So, the formula for option 1 is,
\(\color{#000000 }{ \displaystyle f(n)=100^n+1000 }\)

And the formula for option 2 is,
\(\color{#000000 }{ \displaystyle f(n)=1000\cdot(1.1)^n }\)

in both formulas,
\(\color{#000000 }{ \displaystyle n }\) - the number of years
\(\color{#000000 }{ \displaystyle f(n) }\) - the total amount after n years

Answer 4

am I correctly intepreting your data?

Answer 5

Yes

Answer 6

ok, cool

Answer 7

But, when you plug in n=20, you are plugging it on the right side of the equation as well.

Answer 8

Option 1
\(\color{#000000 }{ \displaystyle f(20)=100^{20}+1000 }\)

Option 2
\(\color{#000000 }{ \displaystyle f(20)=1000\cdot(1.1)^{20} }\)

Answer 9

Okay

Answer 10

\(100^{20}=(10^{2})^{20} =10^{40}\)
And that is \(1\times 10^{40}\) (in scientific notation)

That is a ridiculously huge number!!

Answer 11

Where as \(1.1^{20}\approx 6.73\)

Answer 12

and even if you multiply this times a billion it will still be smaller than \(1\times 10^{40}\).

Answer 13

okay, thank you

Answer 14

f(n) = 100*n + 1000
f(n) = 1000*1.1^n

Answer 15

Don't want to disturb, but why are you reposting these functions again?