Question

Let me post my question right quick. ^_^
Btw, i will give medals. P.s. I just want to know how to solve it, not the answer. ^_^ Thanks a ton!

Answer 1

\[18r ^{4}s ^{5}t ^{6}\div -3r ^{2}st ^{3}\]

Answer 2

\[\frac{a^m}{a^n}=a^{m-n}\]

Answer 3

its a direct application of the above rule

Answer 4

so 18r^4/-3r^2 is r^4-^2 ?

Answer 5

what would you do with the 18, and -3?

Answer 6

\[\frac{18r ^{4}s ^{5}t ^{6}}{-3r ^{2}st ^{3}}\]

Answer 7

or, is there a way to make it 18rst^?

Answer 8

and -3rst^?

Answer 9

\[\frac{18}{-3} \times \frac{r^4}{r^2} \times \frac{s^5}{s} \times \frac{t^6}{t^3}\]

Answer 10

oh, i get it.

Answer 11

simplify the above using the rule
\[\frac{a^m}{a^n}=a^{m-n}\]

Answer 12

so its -6r^2s^5t^3 ?

Answer 13

yep...
but the "s" term is wrong

Answer 14

hw so?

Answer 15

oh, would it be s^4?

Answer 16

yes :)

Answer 17

oh, so if there isnt a ^? than it is automatically -1 from ^5

Answer 18

?

Answer 19

any number raised to the power "1" is the number itself...

for example
\(s=s^1\)

Answer 20

just as i suspected. ok, thanks! ^_^

Answer 21

sure :)