Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (boldjon):

Can someone help https://www.dropbox.com/s/zaqxa4sz16e9a0k/Screenshot%202016-01-01%2014.39.37.png?dl=0

zepdrix (zepdrix):

This value h moves the function h to the `right`,\[\large\rm y=(x-h)^2\] This value k moves the graph `up` by k,\[\large\rm y=x^2+k\]

zepdrix (zepdrix):

Vertical is `up/down`, ya? :)

OpenStudy (boldjon):

so y+x^2+k

OpenStudy (boldjon):

i mean y=x^2+k

zepdrix (zepdrix):

They want you to pick out `the actual number` that is causing the vertical change. It's either the 5 or the 3.

OpenStudy (boldjon):

OHHH

OpenStudy (boldjon):

so y=5^2

zepdrix (zepdrix):

Hmm maybe I made that too confusing :(

zepdrix (zepdrix):

\[\large\rm y=(x-\color{orangered}{h})^2+\color{royalblue}{k}\]This is a horizontal shift of \(\large\rm \color{orangered}{h}\), and a vertical shift of \(\large\rm \color{royalblue}{k}\), And we were given this equation,\[\large\rm y=(x-\color{orangered}{-5})^2+\color{royalblue}{3}\]

OpenStudy (boldjon):

so 3 represents the vertical translation

OpenStudy (boldjon):

so just 3, i don't have to put in an equation of some sort?

zepdrix (zepdrix):

Yes, just 3 :)

OpenStudy (mathmale):

I would write: "That 3 represents the distance that the graph of y=x^2 is to be translated upward." No equation needed, but a verbal explanation surely would be helpful.

OpenStudy (boldjon):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!