The table below shows four systems of equations: (System 1) 4x − 5y = 2 3x − y = 8 (System 2) 4x − 5y = 2 10x − 7y = 18 (System 3) 4x − 5y = 2 3x − 8y = 4 (System 4) 4x − 5y = 2 10x + 3y = 15 Which pair of systems will have the same solution? A.) System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to two times the second equation in system 1 B.) System 2 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 2 to two times the second equation in system 2 C.) System 1 and system 2, because the second equation in system 2 is obtained by adding the first equation in system 1 to three times the second equation in system 1 D.) System 2 and system 3, because the second equation in system 3 is obtained by adding the first equation in system 2 to three times the second equation in system 2
help? @BeautifulMystery. @mathwizzard3 @parker.goodbar @pooja195 @readergirl12
@Nefxrious What is so hard about this? You can just test all the answers out
@Needhelpstudying I tried but I don't understand what they are telling me
@Nefxrious Alright, hold on for a bit, @mathmale is helping me with another question. I'll help you in a bit.
@Needhelpstudying ok!
Hello, Neffy. Pairs of different equations can sometimes have the same solution. You may have to solve all four given systems of linear equations, fnding a solution for each. Are any 2 of these four solutions the same? If so, you've answered this question.
I'm sorry, but need to attend to other things right now. I do urge you to solve all 4 systems of linear equations given you in this problem, and then compare the solutions to see whether or not any 2 are the same.
@Nefxrious do you know how to solve systems of equations?
@Photon336 Yes
Yeah, it's probably just easier to do what @mathmale said and just solve them one by one. we can start by working on the first one
@Photon336 I did that and I got all of them wrong except one but it isn't an answer
sometimes it's better to eliminate one variable and then combine the two equations rather than doing substitution. to get rid of y multiply one by 3 the other by -5 3(4x − 5y = 2) 5(10x + 3y = 15) then combine 12x-15y =6 50x+15y =75 62x = 81 x = 1.31~ 4x-5y = 2 4(1.31)-5y = 2 5.24-5y = 2 y = 0.646 x = 1.31, y = 0.646 4x-5y = 2 4(1.31)-5(0.646) = 2.01
eliminating a variable method is sometimes easier than substitution.
@Photon336 how did you get 3(4x − 5y = 2) 5(10x + 3y = 15)?
so do you notice something? I wanted to get rid of y so i multiplied one equation by 3 and the other by 5 and heres what i got 12x-15y = 6 + 50x+15y = 75 when I add the top and bottom notice something -15y and +15y cancel out. so we're left with 62x = 81 so I multiplied both the top and equation by those numbers.
@Photon336 where did you get 3 and 5 ?
@Nefxrious that wasn't in the problem originally I multiplied the equations by 3 and 5 so I could get rid of y when I combined them.
@Photon336 Oh okay! So I just need to do that for the other equations?
yeah, but that's just for that particular one think to yourself: what numbers would you need to multiply the equations by to eliminate a variable.
you get what I did right? @Nefxrious ?
@Photon336 Yeah! I get! My big problem was trying to cancel out the variable.
the point is canceling out the variables
try this one 4x − 5y = 2 3x − y = 8
ask yourself? what variable do you want to eliminate: pick one
Photon336 I want to eliminate y
okay so We can eliminate this by multiplying the bottom equation by -5 check this out see how this goes. TOP 4x-5y = 2 Bottom -5(3x-y = 8) TOP 4x-5y = 2 BOTTOM -15x+5y = -40 notice when we add these two equations together -5y and +5y cancel out
@Photon336 then you would solve and get -11x=-38 -11/-11x=-38/-11 x= 3.45
Then you can plug 3.45 = x back into the top one and you can get y 4x-5y = 2
@Photon336 4(3.45)-5y=2 13.8-5y=2 13.8-13.8-5y=2-13.8 5y/5=-11.8/5 y=-2.36
Yes nice job y = +2.36 not -2.36 x = 3.45 for this one.
@Photon336 why not negative? I plugged it in and I got 2.
I did it like this 13.8-2 = 11.8/5y = 2.36 let's check our answers they have to satisfy both the equations or else we're wrong. x = 3.45, y =2.36 4x − 5y = 2 4(3.45)-5(2.36) = 2 correct 3(3.45) − 2.36 = 8 correct we find that these two answers are correct b/c we plugged them into the top and bottom equations and got the answers we were supposed to get here.
@Photon336 okay I made the 11.8 a negative
hm, okay but for me i just hate using negative numbers lol so when i can i try to make everything positive
@Photon336 when it looks like this 4x-5y=2 10x-7y=18 would you do -7(4x-5y=2) 5(10x-7y=18)?
Yep you're getting the hang of it when you add those together you'll get -35y and +35y
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