Question

What is the 4th term of



112 square root 2 a4


-112 square root 2 a4


112 square root 2 a5


-112 square root 2 a5

Answer 1

Binomial Theorem

Answer 2

https://static.k12.com/eli/bb/815/-1/0/2_36688_44255/-1/6a31ce8d00245d59047e898d0e88e24266705dce/media/fdb916c8a331ce7224bf067e816a253e1dc34370/mediaasset_672117_1.gif

Answer 3

-112

Answer 4

thanks

Answer 5

@abideinhim square root a4 or a5

Answer 6

If you know Pascal's Triangle and its applications, use that tool to find the coefficients.

Answer 7

\[a^8-8 \sqrt{2} a^7+56 a^6-112 \sqrt{2} a^5+280 a^4-224 \sqrt{2} a^3+224 a^2-64 \sqrt{2} a+16 \]\[-112 \sqrt{2} a^5 \]

Answer 8

the general term \(T_{r-1}\) of any binomial expansion say \((a+b)^n\) is given as->

\(\large T_{r-1}=~^nC_r(a)^{n-r}(b)^r\)

you wanna find \(4^{th}\) term or we can say \(T_4\)
so \(T_{r-1}=T_4\)
so r=5

now just find out \(a,~b,~n\) and put them in the general term equation along with r to get the answer :)

Answer 9

the answer is D