Question

If f(x) = -x+5 and g(x) = x^2, what is the solution set of the equation f(x)=g(x), rounded to the nearest tenth?

Answer 1

\[\large\rm -x+5=f(x)=g(x)=x^2\]Leads us to,\[\large\rm -x+5=x^2\]Solve for x :)

Answer 2

k

Answer 3

Add x to each side,
subtract 5,\[\large\rm 0=x^2+x-5\]Try to factor,
if it doesn't factor,
Quadratic Formula, ya? :)

Answer 4

ok i'll factor
ty

Answer 5

i'll try completing the square

Answer 6

(x+1/2)^2) -(21/4)

Answer 7

oh noes

Answer 8

u left :(

Answer 9

oh sorry :O
i get notification when u post though, so easy to come back

Answer 10

Oh :)

Answer 11

You did completing the square?
Ok that's a fine approach,\[\large\rm 0=\left(x+\frac{1}{2}\right)^2-\frac{21}{4}\]Adding 21/4 to both sides,\[\large\rm \frac{21}{4}=\left(x+\frac{1}{2}\right)^2\]Then square root next, ya?

Answer 12

Quadratic Formula would have been a bit easier than this route XD
But we're already half-way through this hehe

Answer 13

x+ 1/2 = sqrt 21/4

Answer 14

but i can do quad form

Answer 15

(-1 +or- sqrt 21)/2

Answer 16

Ok great!
And it looks like they want us to approximate our solutions to the nearest tenth.
So, calculator time.

Answer 17

yes

Answer 18

\[\large\rm \frac{-1-\sqrt{21}}{2}\approx?\]

\[\large\rm \frac{-1+\sqrt{21}}{2}\approx?\]

Answer 19

1.79
2.79

Answer 20

Hmm, one of those should be negative.

Answer 21

-2.79

Answer 22

yes?

Answer 23

Ok great :)
And make sure you round down to the correct place.
Right now you have the `hundredth place`

Answer 24

1.80
-2.80

Answer 25

Don't include the 0, bad bad bad! XD
That's still the hundredth's place hehe.

1.8 and -2.8

Yay good job \c:/

Answer 26

oh i was worry

Answer 27

thanks

Answer 28

I appreciate

Answer 29

I can become a fan because I already did ;p