if f(x)=5x-4 and g(x)=x^2, what is (g^of)(2)

Question

anonymous · Answer

first find $f(2)$

anonymous · Answer

then whatever you get, find $g(\text{that})$

decarr432 · Answer

How do I find f(2)?

anonymous · Answer

not to be mean, but if you cannot find $f(2)$ then you certainly cannot find $(g\circ f)(2)$

decarr432 · Answer

I am the worst at math ;-;

anonymous · Answer

you evaluate a function at a  number by plugging in the number where you see the variable

anonymous · Answer

for example, if $f(x)=2x+4$ then $f(5)=2\times 5+4=14$

decarr432 · Answer

Okay so simple plug (2) in for all my x's

anonymous · Answer

right
you have $f(x)=x^2$ right?

decarr432 · Answer

g(x)=x^2

anonymous · Answer

ooh ok and $$f(x)=5x-4$$

decarr432 · Answer

yeah

anonymous · Answer

so if $$f(x)=5x-4$$ what is $f(2)$?

decarr432 · Answer

it would be 5(2)-4=6 right and x^2 would be the same as 2*2

anonymous · Answer

wait slow down

anonymous · Answer

you are right, $$f(2)=5\times 2-4=6$$

anonymous · Answer

but now you do not want to compute $g(2)=2^2=4$ 
instead you want to compute $g(6)=6^2$

decarr432 · Answer

okay because 6 is now my new x so I plug it instead of 2. right?

anonymous · Answer

yes

decarr432 · Answer

6^2=36?

anonymous · Answer

in one line it looks like this $$(g\circ f)(2)=g(f(2))=g(6)=36$$

anonymous · Answer

yes 36 is your answer

decarr432 · Answer

Okay thank you sorry for so many questions, I did horrible in match in middle school and its coming to bite me in the butt in highschool lol

anonymous · Answer

that wasn't so hard, was it?

anonymous · Answer

no problem
we can do another if you iike

decarr432 · Answer

No it wasn't thank you so much for the help

decarr432 · Answer

Ill post the next one thanks