Write the equation of the line in point intercept form. Points on the line: (-9,-8) & (2,-4)
i think its `point slope` form or slope intercept form
Yeah, I meant to write Slope intercept form.
\[\large\rm y-y_1=m(x-x_1)\] point slope form where m is the slope and (x_1,y_1) represent one of the given point and the slope intercept form is \[\large\rm y=mx+b\] where m is slope and b is y-intercept
do you know the slope formula ? formula to find slope ?
Is the slope 4/11?
how did you get that ?? :)
I used the slope formula to find the slope.
good whats the formula show your work plz :) what numbers did you substitute in to get 4/11for slope ?
\[m=\left[\begin{matrix}y2 - y1 \\ x2 - x1\end{matrix}\right]\]
hmm looks good i guess and its fraction \[\rm \frac{ y_2-y_1 }{ x_2-x_1 }=m\] what did you substitute for x_1,x_2 & y_1,y_2?
The points on the line
x__-9__1 x___2___2 y___-8___1 y______-4___2 @Nnesha
cool and there is a negative in the formula but remember y's values should be at the top of fraction and x at the bottom and don't forget the sign \[\rm \frac{ -8 -(-4) }{ -9-2 }=m\] now simplify that
How is -8 y2?
-4/-11?
that's y_1 i thought you typed y_! and x_1 first and then y_2 x_2
\[\rm \frac{ y_1-y_2 }{ x_1-x_2}=\frac{y_2-y_1}{x_2-x_1}\] doesn't matter which one comes first you will get the same answer
and yes that's correct now just cancel out the negative signs and then substitute m for the slope value into the slope intercept form which is y=mx+B and then pick one order (doesn't matter which one u use) substitute x and y for the values in order pair into the equation and then solve for b(y-intercept)
order pair*
So 4/11 is positive?
correct.
So what do substitute for y and b
alright \[\rm y=mx+B\] m is slope which is 4/11 and b is y-intercept that you have to find so first of all substitute m for 4/11 and pick one of the order pair for x and y substitute x and y for that their values and then solve for b
\[\rm y=\frac{4}{11}x+b\] substitute x and y for (-9,-8) OR for (2,-4) and then solve for b
\[-4= \frac{ 4 }{ 11 }2 + b ?\]
How do I solve for b?
you should put the parentheses it's m times x so it should be \[\rm -4 =\frac{4}{11}(2)+b\] first multiply slope by the x value
8/11?
correct \[-4=\frac{8}{11}+b\] solve for b cancel out the 8/11 from right side
Do I multiply it?
it's `8/11 PLUS b` addition so do opposite of addition to cancel it out
8/11 - 8/11?
correct subtract -8/11 both sides
.-.
wat ?? ,-, subtract 8/11 both sides ?? .-.
i have to go ... can you solve for b ?? do you understand that ? ?
No..
alright what part u not able to solve let me know so we can do it together
The subtracting from both sides
I'm good with everything else.
subtract 8/11 both sides\[\rm -4\color{Red}{-\frac{8}{11}}= \frac{8}{11}\color{Red}{-\frac{8}{11}}+b\] at right side positive 8/11 and negative 8/11 would cancel each other out(That was the goal)
\[\rm -4\color{Red}{-\frac{8}{11}}= \cancel{\frac{8}{11}\color{Red}{-\frac{8}{11}}}+b\] get the common denominator at left side
brb
here is an example \[\rm \frac{ a }{ b }-\frac{ c }{ d }\] when the denominators aren't the same multiply the denominators of both fraction |dw:1451719593948:dw| and multiply the numerator of first fraction with the denominator of 2nd fraction multiply the numerator of 2nd fraction with the denominator of first fraction that's it
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