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Integration Just to double check my answer
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Given\[y=(3x-4)^5\],find dy/dx.Hence,find\[\int\limits_{}^{}(3x-4)^4\]
\[\int\limits_{}^{}(3x-4)^4dx\]
dy/dx = .. ?
i got\[\frac{ dy }{ dx }=15(3x-4)^4\]
@MARC_ thats differentiation not integration
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do u want to integrate the expression or differentiate ?
First differentiate,then integrate
correct. and the integral?
i got\[\int\limits_{}^{}(3x-4)^4dx=\frac{ 1 }{ 15 }(3x-4)^5\]
\(\huge \checkmark \)
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Thank you @hartnn :)
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