Question

Integration
Just to double check my answer

Answer 1

If\[\frac{ d }{ dx }\frac{ 5x }{ (2x+1) }=\frac{ 5 }{ (2x+1)^2 }\],

Answer 2

find\[\int\limits_{}^{}\frac{ 1 }{ (2x+1)^2 }dx\]

Answer 3

so, did you get x/(2x+1) ?

Answer 4

yes

Answer 5

this one was easier then previous ones :P

Answer 6

okay, lol
But,thank you @hartnn\[\huge{:)}\]

Answer 7

wait, are you sure you calculated derivative correctly?

Answer 8

do u want to c my working..maybe u can check it

Answer 9

the final answer should have been -1/[2(2x+1)]

Answer 10

yes please

Answer 11

okay

Answer 12

This is my working..\[\int\limits_{}^{}\frac{ 5 }{ (2x+1)^2 }dx=\frac{ 5x }{ 2x+1 }\]\[5\int\limits_{}^{}\frac{ 1 }{ (2x+1)^2 }dx=\frac{ 5x }{ 2x+1 }\]\[\int\limits_{}^{}\frac{ 1 }{ (2x+1)^2 }dx=\frac{ 1 }{ 5 }(\frac{ 5x }{ 2x+1 })\]\[=\frac{ x }{ 2x+1 }\]

Answer 13

ok, yes its correct!

seems that this x/(2x+1) is just another equivalent answer!

Answer 14

Thank you @hartnn\[\huge{:)}\]

Answer 15

welcome \[\huge{:)}\]