Question

In a city school, 60% of students have blue eyes, 55% have dark hair, and 35% have blue eyes and dark hair. What is the probability (rounded to the nearest whole percent) that a randomly selected student has dark hair, given that the student has blue eyes?

58%
20%
80%
64%

Answer 1

Oh hello there

Answer 2

Hi lol

Answer 3

Can anyone help?

Answer 4

I dont know how. Give me a few minutes

Answer 5

OK

Answer 6

given that P(blue eye)=P(A)=60%=0.6
P(dark hair)=P(B)=55%=0.55
P(A intersection B)=35%=0.35

Answer 7

this problem of conditional probabilty

Answer 8

Ok one sec

Answer 9

How do I go about solving this though? What goes where? How do I set it up?

Answer 10

P(B/A)=P(A interscetion B)/P(A)

Answer 11

simply put values

Answer 12

Snufflebug02 do you still need explanation

Answer 13

Kind of I don't know how to solve it

Answer 14

since its select dark hair but its given that that has blue eye

Answer 15

formula if select an event A but its given that event B then P(A/B)=P(A and B)/P(B)

Answer 16

It asks for people who have dark hair and blue eyes. 55% have dark hair and 35% have dark hair and blue eyes. So it is 35 people out of 55. Thats why Er.Mohd.AMIR said 35 divided by 55. I hope you understand

Answer 17

need more explanation

Answer 18

OK thanks