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Mathematics 23 Online
OpenStudy (cublade):

For f(x)=3x(x^2+1)(x+3)^2, list each real zero and its multiplicity. Determine whether the graph crosses or touches the x-axis at each x-intercept.

OpenStudy (b87lar):

i can help but would like us to walk through it together so that you learn: can you take a first stab at it? What would be the first easy-to-spot zero of the function f(x)?

OpenStudy (cublade):

Well for the 3x, the zero would probably be zero.

OpenStudy (b87lar):

correct!

OpenStudy (cublade):

And for the (x+3)^2, it would be -3.

OpenStudy (b87lar):

perfect, and that one qould have multiplicity of 2 because of the square, like (x+3)(x+3)

OpenStudy (b87lar):

now the middle part is a term x^2+1 so the question is when is that term 0?

OpenStudy (cublade):

That's correct. But to balance out that section wouldn't x^2 have to equal -1?

OpenStudy (b87lar):

yes, it would, and that is why they mention "real" zeros - as opposed to "imaginary" ones. The equation \[x^2=-1\] has a solution but only in imaginary numbers, namely it is the number \[i\].

OpenStudy (b87lar):

so that is an imaginary zero and is not part of the solution they are asking for

OpenStudy (cublade):

So are the zeros 0, i, and -3?

OpenStudy (b87lar):

yes 0 (multipl. 1), -3 (multipl. 2) would be the answer to the problem. and yes "i" is another zero (but not real)

OpenStudy (b87lar):

do you know what to do about the second part of the question?

OpenStudy (cublade):

It's when the multiplicities are even or odd, correct?

OpenStudy (cublade):

Even bounces and odd crosses?

OpenStudy (b87lar):

yes you got it

OpenStudy (cublade):

Thanks again.

OpenStudy (b87lar):

yw!

OpenStudy (anonymous):

Refer to the attached plot.

OpenStudy (cublade):

Thanks!

OpenStudy (b87lar):

very nice @robtobey

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