For f(x)=3x(x^2+1)(x+3)^2, list each real zero and its multiplicity. Determine whether the graph crosses or touches the x-axis at each x-intercept.
i can help but would like us to walk through it together so that you learn: can you take a first stab at it? What would be the first easy-to-spot zero of the function f(x)?
Well for the 3x, the zero would probably be zero.
correct!
And for the (x+3)^2, it would be -3.
perfect, and that one qould have multiplicity of 2 because of the square, like (x+3)(x+3)
now the middle part is a term x^2+1 so the question is when is that term 0?
That's correct. But to balance out that section wouldn't x^2 have to equal -1?
yes, it would, and that is why they mention "real" zeros - as opposed to "imaginary" ones. The equation \[x^2=-1\] has a solution but only in imaginary numbers, namely it is the number \[i\].
so that is an imaginary zero and is not part of the solution they are asking for
So are the zeros 0, i, and -3?
yes 0 (multipl. 1), -3 (multipl. 2) would be the answer to the problem. and yes "i" is another zero (but not real)
do you know what to do about the second part of the question?
It's when the multiplicities are even or odd, correct?
Even bounces and odd crosses?
yes you got it
Thanks again.
yw!
Refer to the attached plot.
Thanks!
very nice @robtobey
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