Question

Algebra Gelp PPPLLLEEEAAASSSEEE medal+Fan

Answer 1

@mathmale

Answer 2

Come on @steve816

Answer 3

?

Answer 4

basically extraneous solution are not equal products

Answer 5

for example square root of 2-1 = 1 but if square root of 1-2 then the answer would be square root of -1 so it becomes imaginary number or in other word "extraneous solution
\[\sqrt{2-1}=1 \]
\[\sqrt{1}=1 \]
1=1 is not extraneous solution
But
\[\sqrt{1-2}=1 \]
\[\sqrt{-1}=1 \]
then this is extraneous solution.

Answer 6

ok so i need to create a true equation?

Answer 7

yea as it said you have to give value for a,b,c,d and then create 2 different problem like above.

Answer 8

So would \[\sqrt[4]{x}+5+7\] ?

Answer 9

would that work?

Answer 10

maybe I don't know but I think you might wanna make it easy to solve though lol

Answer 11

ok so \[\sqrt[1]{x}+4+4\]

Answer 12

\[\sqrt[1]{x} + 4 + 4 = 11\]
11 is D

Answer 13

are you allow to eliminate the square root or no?

Answer 14

idk

Answer 15

i mean I would just do like this, if allow to eliminate √: \[\sqrt[2]{x^{2}} +2 +5 = x+7\]

Answer 16

the product would be x+7= x+7

Answer 17

i send pic of entire assignment

Answer 18

nevermind I totally get your assignment now

Answer 19

ok let me as you what value would you like to give for constants a,b,c, and d?

Answer 20

i'll help you create the problem.

Answer 21

are you there? lol

Answer 22

yeah sorry

Answer 23

now it make more sense

Answer 24

Hows that

Answer 25

so like I said what values would you like to give for a b c d?

Answer 26

then plug them in \[\sqrt[a]{x+b}+c =d\]

Answer 27

6, 4, 13

Answer 28

ok so \[\sqrt[2]{x+6}+4=13\] is that what you like to have?

Answer 29

Sure But its \[2\sqrt{x+6}+4=13\]

Answer 30

ok so since you have got your equation you want to give 2 values for the variable x. One for extraneous solution and the other for non exraneous solution.

Answer 31

ok so we need to solve. Right?

Answer 32

so let's give x=10 and the other x = -22

Answer 33

yea we are gonna solve it

Answer 34

done

Answer 35

Hows This

Answer 36

almost correct

Answer 37

yaaaay!!!!

Answer 38

before you subtract 6, you need to get rid of square root first

Answer 39

Now?

Answer 40

no? am i suppose to find what 4.5 is the square root of?

Answer 41

no, you need to square both sides to get rid of the square root

Answer 42

so square 4.5?

Answer 43

yea and that's = x+6

Answer 44

20.25?

Answer 45

you should get 20.25

Answer 46

yes and now subtract 6

Answer 47

@SkepticGod
Can you help me out when you get time?

Answer 48

lol my brain is about to explode even this problem

Answer 49

but sure i'll try @Atsie

Answer 50

@CJDOG so you should get x= 14.25

Answer 51

There we GO

Answer 52

yep

Answer 53

I'm just desperate. MY brain is about to explode because of confusion and no one's helping me!
(whenever you get time @SkepticGod )

Answer 54

and for extraneous solution, you can plug in X for any number that is not equal to 14.25

Answer 55

@Atsie what level math?

Answer 56

ok so 15

Answer 57

yea that's work

Answer 58

@CJDOG
High school algebra

Answer 59

plug in 15 for x and if you see the answer is different then it is an extraneous solution

Answer 60

OK thanks

Answer 61

for now i will go help @Atsie if you have any other help I'll try again later

Answer 62

you're welcome!