I don't want the direct answer, I want someone to help me understand how to solve the problem, and how to get to the answer. There are some tables and I don't wanna format them, so I have attached a word document with the tables inside it, The Word Document is in the comments below. Thank you for helping!
@triciaal @sleepyjess @Hero @ParthKohli @pooja195 @TheSmartOne @Michele_Laino @mathmale @mathstudent55 @boldjon @zepdrix Help Please! Thanks!
@triciaal ?
@Jaynator495 You wanted me to tag you for some reason
quadratic function, h(x) = 7.84x2 + 1022.16. what value of x will produce the maximum?
do you know how to start with this problem?
@triciaal How do you find the maximum x value?
-b/2a where the equation is ax^2 +bx + c
you can read more about it here too http://www.mathwarehouse.com/geometry/parabola/vertex-of-a-parabola.php
Alright, -b/2a
Not sure why look for a maximum of a parabola here since the parabola is convex and x for which it is maximum is infinity... I can offer an alternative way to solution, but I 'd like to know what the OP already did first. Pls let me know.
h(x) = 7.84x2 + 1022.16.
lets see I think 1022.16 is b
and 7.84 is a?
Or wait... am I doing this wrong @triciaal ?
what is the value in f(x) when x = 11.42? what is the value in g(x) ? compare all these
@triciaal Why 11.42?
f (x) = 30x + 1000\ g (x) = 1000(1.03)x h(x) = 7.84x2 + 1022.16.
f (11.42) = 30x + 1000 f (11.42) = 30(11.42) + 1000 f (11.42) = 342.6 + 1000 f(11.42) = 1342.6
@Needhelpstudying Here is my suggestion: create a table for the quadratic function for x=1,2,3, and 4. Then, compare - that will give you the basis for answering both questions.
sorry
g(11.42) = 1000(1.03)^11.42 g(11.42) = 1000(1.40152583) g(11.42) = 1401.52583
h(11.42) = 7.84x^2 + 1022.16 h(11.42) = 7.84(11.42)^2 + 1022.16 h(11.42) = 7.84(130.4164) + 1022.16 h(11.42) = 1022.46458 + 1022.16 h(11.42) = 2044.62458
Follow @b87lar 's sugesstion
@triciaal Why 11.42? f(11.42) = 1342.6 g(11.42) = 1401.52583 h(11.42) = 2044.62458
@b87lar won't the quadratic function eventually go down though?
let me draw a sketch of the function |dw:1451775033986:dw|
the parabola will go up as you increase x (years). Now it is important to verify if it grows faster than the linear function, and than the exponential function - for that I suggest calculating the values for x = 1, 2, 3, and 4. You can directly compare them with the ones you have in the original word doc.
@b8ylar I just graphed h(x) = 7.84x2 + 1022.16, and it's upside down...
@b87lar
@triciaal Can you help?
@triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal
@zepdrix
NVM Don't need help thanks anyways bye
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