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Mathematics 16 Online
OpenStudy (anonymous):

I don't want the direct answer, I want someone to help me understand how to solve the problem, and how to get to the answer. There are some tables and I don't wanna format them, so I have attached a word document with the tables inside it, The Word Document is in the comments below. Thank you for helping!

OpenStudy (anonymous):

@triciaal @sleepyjess @Hero @ParthKohli @pooja195 @TheSmartOne @Michele_Laino @mathmale @mathstudent55 @boldjon @zepdrix Help Please! Thanks!

OpenStudy (anonymous):

@triciaal ?

OpenStudy (anonymous):

@Jaynator495 You wanted me to tag you for some reason

OpenStudy (triciaal):

quadratic function, h(x) = 7.84x2 + 1022.16. what value of x will produce the maximum?

OpenStudy (b87lar):

do you know how to start with this problem?

OpenStudy (anonymous):

@triciaal How do you find the maximum x value?

TheSmartOne (thesmartone):

-b/2a where the equation is ax^2 +bx + c

TheSmartOne (thesmartone):

you can read more about it here too http://www.mathwarehouse.com/geometry/parabola/vertex-of-a-parabola.php

OpenStudy (anonymous):

Alright, -b/2a

OpenStudy (b87lar):

Not sure why look for a maximum of a parabola here since the parabola is convex and x for which it is maximum is infinity... I can offer an alternative way to solution, but I 'd like to know what the OP already did first. Pls let me know.

OpenStudy (anonymous):

h(x) = 7.84x2 + 1022.16.

OpenStudy (anonymous):

lets see I think 1022.16 is b

OpenStudy (anonymous):

and 7.84 is a?

OpenStudy (anonymous):

Or wait... am I doing this wrong @triciaal ?

OpenStudy (triciaal):

what is the value in f(x) when x = 11.42? what is the value in g(x) ? compare all these

OpenStudy (anonymous):

@triciaal Why 11.42?

OpenStudy (anonymous):

f (x) = 30x + 1000\ g (x) = 1000(1.03)x h(x) = 7.84x2 + 1022.16.

OpenStudy (anonymous):

f (11.42) = 30x + 1000 f (11.42) = 30(11.42) + 1000 f (11.42) = 342.6 + 1000 f(11.42) = 1342.6

OpenStudy (b87lar):

@Needhelpstudying Here is my suggestion: create a table for the quadratic function for x=1,2,3, and 4. Then, compare - that will give you the basis for answering both questions.

OpenStudy (triciaal):

sorry

OpenStudy (anonymous):

g(11.42) = 1000(1.03)^11.42 g(11.42) = 1000(1.40152583) g(11.42) = 1401.52583

OpenStudy (anonymous):

h(11.42) = 7.84x^2 + 1022.16 h(11.42) = 7.84(11.42)^2 + 1022.16 h(11.42) = 7.84(130.4164) + 1022.16 h(11.42) = 1022.46458 + 1022.16 h(11.42) = 2044.62458

TheSmartOne (thesmartone):

Follow @b87lar 's sugesstion

OpenStudy (anonymous):

@triciaal Why 11.42? f(11.42) = 1342.6 g(11.42) = 1401.52583 h(11.42) = 2044.62458

OpenStudy (anonymous):

@b87lar won't the quadratic function eventually go down though?

OpenStudy (b87lar):

let me draw a sketch of the function |dw:1451775033986:dw|

OpenStudy (b87lar):

the parabola will go up as you increase x (years). Now it is important to verify if it grows faster than the linear function, and than the exponential function - for that I suggest calculating the values for x = 1, 2, 3, and 4. You can directly compare them with the ones you have in the original word doc.

OpenStudy (anonymous):

@b8ylar I just graphed h(x) = 7.84x2 + 1022.16, and it's upside down...

OpenStudy (anonymous):

@b87lar

OpenStudy (anonymous):

@triciaal Can you help?

OpenStudy (anonymous):

@triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal @triciaal

OpenStudy (anonymous):

@zepdrix

OpenStudy (anonymous):

NVM Don't need help thanks anyways bye

OpenStudy (triciaal):

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