Question

Statistics honors project check @ganeshie8

Answer 1

hold on let me upload the work

Answer 2

1. Use the sample data on Pages 1 and 2 in the Worksheet.doc file to determine the proportion of times a flight in each sample was delayed. Remember, delay times are positive. Record the sample proportions on Page 4.

Answer 3

yes those pages are from the worddocument I uploaded

Answer 4

Total how many observations are there in January 2011 ?

Answer 5

40

Answer 6

In how many of those observations, the flights are delayed ? (positive delay)

Answer 7

9 excluding the 0's because those are neutral right?

Answer 8

right, but im getting 10
count again

Answer 9

yes sorry you are correct they are 10

Answer 10

So whats the proportion(ratio) of "number of delayed flights" to "toal number of flights" ?

Answer 11

10/40

Answer 12

1/4

Answer 13

Yep, similarly find the proportion for June 2011 table too

Answer 14

alright brb

Answer 15

3/40

Answer 16

Part 3 [After Lesson 6.6: Proportion Differences]

Jan : \( p_1=1/4\)
June : \(p_2=3/40\)

Margin of error = \(Z^*\times\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}\\~\\
=1.96\times\sqrt{\dfrac{\frac{1}{4}(1-\frac{1}{4})}{40}+\dfrac{\frac{3}{40}(1-\frac{3}{40})}{40}}\\~\\
=0.157\)

Confidence interval = \((p_1-p_2) \pm \text{margin of error} \\~\\
=(\frac{1}{4}-\frac{3}{40}) \pm 0.157\\~\\
=(0.018,~0.332)
\)

Interpretation : We say that we are \(95\%\) confident that the difference between the two population proportions, \(p_1-p_2\), lies betweenhe calculated limits since, in repeated sampling, about \(95\%\) of the intervals constructed this way would contain \(p_1-p_2\)