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Mathematics 7 Online
OpenStudy (anonymous):

When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 86%? a.0.14 b.0.86 c.0.93 d.0.99

OpenStudy (owen3):

I believe you find the z score here

OpenStudy (anonymous):

how do i do that

OpenStudy (anonymous):

i really need help plz help me

OpenStudy (marihelenh):

@owen3 He doesn't know z-scores, normal distributions, or percentiles.

OpenStudy (owen3):

critical probability = 1 - alpha/2

OpenStudy (anonymous):

which means?

OpenStudy (anonymous):

is the answer a?

OpenStudy (owen3):

alpha = 1 - Confidence Level therefore alpha = 1- .86 = .14 alpha/2 = .14/2 = ,07 critical probability = 1- alpha/2 = 1- .07 =

OpenStudy (anonymous):

so the answer is a?

OpenStudy (owen3):

are we allowed to give answers?

OpenStudy (anonymous):

yes

OpenStudy (owen3):

yes that is the answer

OpenStudy (anonymous):

ok thank you

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