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The function s(V) = \[\sqrt[3]{x}\] describes the side length, in units, of a cube with a volume of V cubic units. Jason wants to build a cube with a minimum of 64 cubic centimeters. What is a reasonable range for s, the side length, in centimeters, of Jason’s cube?
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\[s \ge 0\]\[s \ge 4\]\[s \ge 8\]\[s \ge 16\]
\[\sqrt[3]{x}=64\] since volume of square equal to 64
can u find x value
I will try
no, I don't think I ever learned how to do that
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\[\sqrt[3]{x }=x ^{\frac{ 1 }{ 3 }}\] x^1/3 = 4^3 { 64 = 4*4*4 = 4^3]
i will explain it again \[s(v) =\sqrt[3]{x}\] \[s(64) = \sqrt[3]{64}\]
so B, \[s \ge 4\]
exactly
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