What is the 15th term in the sequence? 3 , 12 , 48 , 192 , 768, . . .
Do you know the first step to solving this problem?
First you apply the formula, do you know what that is?
an+a1+(n-1)d
this is a geometric sequence
no arithmetic
how do you figure out whether the series is arithmetic or geometric?
this is a geometric sequence with a common ration of 4
@Morameme1 do you know how?
An arithmetic sequence goes from one term to the next by always adding (or subtracting) the same value.
A geometric sequence goes from one term to the next by always multiplying (or dividing) by the same value.
why? because each term after the first is being multiply by the first number and a fix number?
previous number by a fixed value
You need to multiply by 4.
Until you get to the 12th number, and add.
therefore this will make it a geometric and not arithmetic :D
oh okay
Add them all together. Like: 3*4= 12; 12*4= 48; 48*4=192 and so on.. When you get to your 12th number, add them all up then you should get - 16777215
Understand?
yea thx
You're welcome.
t1= 3 t2=12 t3= 48 t4= 192 observe t2/t1= t3/t2= t4/t3= 4 therefore common ratio (r) =4 the sequence is in geometic progression
t15 =a*r^14 here a= first term = 3 r= 4 plug in the values and get t15
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