For f(x) = 0.01(2)x, find the average rate of change from x = 12 to x = 15.
so evaluate with the given values of x
try that first
\[\text{average rate of change} = \frac{ f(b)-f(a) }{ b-a }\] x= 12= a, x=15=b
i dont understand
do you know what a SLOPE is?
yes
For f(x) = 0.01(2)x, find the average rate of change from x = 12 to x = 15 For f(x) = 0.01(2)x is the same as saying y = 0.01(2) x now we have two values of x's provided and we need to evaluate them one at a time \(x_1 = 12 \) and \(x_2 = 15 \) \(y_1 = 001(2) x_1 \rightarrow y_1 = 001(2) *12\) \(y_2 = 001(2) x_2 \rightarrow y_2 = 001(2) * 15\) after we evaluate each y's, we use the SLOPE formula \( \dfrac{y_2-y_1}{x_2-x_1} \) because AVERAGE rate is just the same as the SLOPE.
there's a period in there 0.01 but it didn't go through my bad.
so would x1 and x2 and y1 and y2 be the same?
yes something similar to when you are learning slopes
so does that mean y1=.24 and y2=.3?
I do not have a calculator so I am not sure.
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