Mathematics
20 Online
OpenStudy (anonymous):
Need help with this this is the link
http://assets.openstudy.com/updates/attachments/56896bf6e4b01857db8e49fe-whateven-1451846662710-1.png
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OpenStudy (z4k4r1y4):
the graph tells you that when x=0 y=1 and when x=1 y=6. which eqution gives these values?
OpenStudy (anonymous):
change in y = change in x
OpenStudy (anonymous):
y=mx+c
OpenStudy (anonymous):
i don't know please tell me
OpenStudy (z4k4r1y4):
from the three possible equations given, put x=0 and x=1 into each of them.
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OpenStudy (anonymous):
i don't understand can please start again
OpenStudy (z4k4r1y4):
ok so you have to match one of the equations to the graph
OpenStudy (z4k4r1y4):
to do this you have to first understand what information the graph is giving you
OpenStudy (anonymous):
okay
OpenStudy (z4k4r1y4):
so when you look at the graph you can see that when x=0 y=1.
Meaning the graph crosses the y-axis at y=1
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OpenStudy (z4k4r1y4):
do you follow?
OpenStudy (anonymous):
yes
OpenStudy (z4k4r1y4):
can you see that at x=1, y=6?
OpenStudy (anonymous):
yes
OpenStudy (z4k4r1y4):
great! so that's the information we have from the graph
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OpenStudy (anonymous):
so the answer will be f[x]=x^6
OpenStudy (z4k4r1y4):
yes
OpenStudy (anonymous):
oooo yeah thanks
OpenStudy (z4k4r1y4):
you're welcome.