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Mathematics 20 Online
OpenStudy (anonymous):

Need help with this this is the link http://assets.openstudy.com/updates/attachments/56896bf6e4b01857db8e49fe-whateven-1451846662710-1.png

OpenStudy (z4k4r1y4):

the graph tells you that when x=0 y=1 and when x=1 y=6. which eqution gives these values?

OpenStudy (anonymous):

change in y = change in x

OpenStudy (anonymous):

y=mx+c

OpenStudy (anonymous):

i don't know please tell me

OpenStudy (z4k4r1y4):

from the three possible equations given, put x=0 and x=1 into each of them.

OpenStudy (anonymous):

i don't understand can please start again

OpenStudy (z4k4r1y4):

ok so you have to match one of the equations to the graph

OpenStudy (z4k4r1y4):

to do this you have to first understand what information the graph is giving you

OpenStudy (anonymous):

okay

OpenStudy (z4k4r1y4):

so when you look at the graph you can see that when x=0 y=1. Meaning the graph crosses the y-axis at y=1

OpenStudy (z4k4r1y4):

do you follow?

OpenStudy (anonymous):

yes

OpenStudy (z4k4r1y4):

can you see that at x=1, y=6?

OpenStudy (anonymous):

yes

OpenStudy (z4k4r1y4):

great! so that's the information we have from the graph

OpenStudy (anonymous):

so the answer will be f[x]=x^6

OpenStudy (z4k4r1y4):

yes

OpenStudy (anonymous):

oooo yeah thanks

OpenStudy (z4k4r1y4):

you're welcome.

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