Law of sines question!
|dw:1451875905109:dw|
What is the value of x?
Remember your law of sines? :) \(\large\rm \frac{\sin(A)}{a}=\frac{\sin(B)}{b}\) Where side a is opposite angle A, and same for the b's.
So um... which angle is opposite the side length labeled 14? :)
yes, which one is angle a,b, and c in this case though?
14 and 45 match and x and 60 match
|dw:1451876083777:dw|Good good good :) So thats the information we'll want to use.
is 14 A?
I was calling the angles the capital letters, so I guess A=45, a=14, ya? ^^
yes, makes sense
Do you think you can plug in the pieces of information correctly? Get this kind of setup? :)\[\large\rm \frac{\sin(A)}{a}=\frac{\sin(B)}{b}\]
14/45=x/60
Oh boy, you didn't use your sine function at all XD
sin14/sin45=sinx/sin60
Oh you :P lol
the sine dosnt go before the denominator does it?
Correct, we apply sine to `angles`.
numerator*
The denominator is a side length :) No sine for him.
okay
wait so then shouldnt it be 45sin/15 and 60sin/x
Mmm ok looks good besides that small typo you made :)\[\large\rm \frac{\sin(45)}{14}=\frac{\sin(60)}{x}\]Now we solve for x. Just a few little algebra tricks.
oh I misrea what you wrote lol XD
darn I spilled the beans :d
When we take this proportion, the `sine of an angle` to the `side opposite that angle`, Law of Sines is telling us that this proportion is always the same regardless of which side/angle pair we choose.
yes
Anyway, we take the sine of the angles, the angles are 45 and 60 degrees in this case. sin(45)/14 = sin(60)/x Hopefully that's not too confusing D:
so what we already did was right
Yes, we're here currently :)\[\large\rm \frac{\sin(45)}{14}=\frac{\sin(60)}{x}\]Have you learned about your "special angles" yet? sin(45) and sin(60) work out to nice values that we don't need a calculator for.
Hmm I may have but i need a refresher
|dw:1451876743338:dw|
Join our real-time social learning platform and learn together with your friends!