Law of sines, help!
|dw:1451877966195:dw|
solve for the missing side lengths
Oh they labeled the vertices A, B and C. That's helpful. Do you see which side they gave us? Side length b=14, ya?
-Yes I see this
@zepdrix cant you set up the equation like so-given the info on the triangle already; sin112/x=sin28/14
|dw:1451879227502:dw|just so we're clear about which side you're calling x.
BTW, you can flip both sides of the fraction if it's more useful for you.\[\large\rm \frac{x}{\sin(112)}=\frac{14}{\sin(28)}\]
okay so at this point I am interested in finding x first, can we do that/ or is it smarter to find y?
okay let me try. I mean its the same as the last one. Just gotta use cross multiplication
Notice how the x is no longer in the denominator? Makes things a little easier :) Unless you're cross multiplying, then I guess it doesn't matter.
You don't NEED to cross multiply though. Notice that x is being divided by sin(112), so you only need to multiply both sides by sin(112) to isolate the x. No big deal though
So then sin112(14)/sin28
oh okay!
oh youre saying if we flipped it. Okay
14sin(112)/sin(28) ok looks good. Calculator time :)
Yes, sorry. If we had flipped it, then cross-multiply is not necessary.
okay but to me the cross multiply way seems more clear
Ok np :)
so lets just stick with it. Im going to plug it into a calculator
Well I get 27.65 but I want it as a number with a square root.
Oo I don't think we can leave it as an exact value for this problem... 112 and 28 are strange values, it would require a ton of work. You want to approximate :) 27.65 sounds good!
really? Okay cool.
now we have to find the other side
cant we just say (sin28/14)/(sin40/y)
oops I meant to set those equal
Good good good. Notice that you COULD use the other set of values, but since your x is an `approximation`, it's better to use the side that is not x :)
sin28/14=sin40/y
ya, good times
Yes, cool
I get y=19.17
Mmm k good \c:/
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