Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (cutiecomittee123):

Law of sines, help!

OpenStudy (cutiecomittee123):

|dw:1451877966195:dw|

OpenStudy (cutiecomittee123):

solve for the missing side lengths

zepdrix (zepdrix):

Oh they labeled the vertices A, B and C. That's helpful. Do you see which side they gave us? Side length b=14, ya?

OpenStudy (cutiecomittee123):

-Yes I see this

OpenStudy (cutiecomittee123):

@zepdrix cant you set up the equation like so-given the info on the triangle already; sin112/x=sin28/14

zepdrix (zepdrix):

|dw:1451879227502:dw|just so we're clear about which side you're calling x.

zepdrix (zepdrix):

BTW, you can flip both sides of the fraction if it's more useful for you.\[\large\rm \frac{x}{\sin(112)}=\frac{14}{\sin(28)}\]

OpenStudy (cutiecomittee123):

okay so at this point I am interested in finding x first, can we do that/ or is it smarter to find y?

OpenStudy (cutiecomittee123):

okay let me try. I mean its the same as the last one. Just gotta use cross multiplication

zepdrix (zepdrix):

Notice how the x is no longer in the denominator? Makes things a little easier :) Unless you're cross multiplying, then I guess it doesn't matter.

zepdrix (zepdrix):

You don't NEED to cross multiply though. Notice that x is being divided by sin(112), so you only need to multiply both sides by sin(112) to isolate the x. No big deal though

OpenStudy (cutiecomittee123):

So then sin112(14)/sin28

OpenStudy (cutiecomittee123):

oh okay!

OpenStudy (cutiecomittee123):

oh youre saying if we flipped it. Okay

zepdrix (zepdrix):

14sin(112)/sin(28) ok looks good. Calculator time :)

zepdrix (zepdrix):

Yes, sorry. If we had flipped it, then cross-multiply is not necessary.

OpenStudy (cutiecomittee123):

okay but to me the cross multiply way seems more clear

zepdrix (zepdrix):

Ok np :)

OpenStudy (cutiecomittee123):

so lets just stick with it. Im going to plug it into a calculator

OpenStudy (cutiecomittee123):

Well I get 27.65 but I want it as a number with a square root.

zepdrix (zepdrix):

Oo I don't think we can leave it as an exact value for this problem... 112 and 28 are strange values, it would require a ton of work. You want to approximate :) 27.65 sounds good!

OpenStudy (cutiecomittee123):

really? Okay cool.

OpenStudy (cutiecomittee123):

now we have to find the other side

OpenStudy (cutiecomittee123):

cant we just say (sin28/14)/(sin40/y)

OpenStudy (cutiecomittee123):

oops I meant to set those equal

zepdrix (zepdrix):

Good good good. Notice that you COULD use the other set of values, but since your x is an `approximation`, it's better to use the side that is not x :)

OpenStudy (cutiecomittee123):

sin28/14=sin40/y

zepdrix (zepdrix):

ya, good times

OpenStudy (cutiecomittee123):

Yes, cool

OpenStudy (cutiecomittee123):

I get y=19.17

zepdrix (zepdrix):

Mmm k good \c:/

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!