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Have you considered the 1st Derivative?
The first derivative is equal to 0
Is that suppose to be t and not x
its supposed to be t.
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Ok so what's the derivative
0
Why
Use the chain rule
Because its with respect to t. the constant e^sinx = 0 for the derivative
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You just told me it was suppose to be t
I thought you meant the s(t) part. Its s(t)=e^sinx
As stated, there are infinitely many values for t where s'(t) = 0, since s(t) is a constant with some odd, unknown parameter, x. We have a problem statement that is incorrect. Let's not work with that. The corrected problem statement should say, \(s(t) = e^{\sin(t)}\) Please calculate s'(t) for this definition.
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