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Mathematics 20 Online
OpenStudy (arianna1453):

Fan + Medal Calculus Help Please

OpenStudy (arianna1453):

OpenStudy (anonymous):

Hey do you know implicit differentiation?

OpenStudy (arianna1453):

OpenStudy (arianna1453):

That is what i got so far

OpenStudy (anonymous):

Your notation is a bit confusing, it's \[\frac{ dy }{ dx }\]

OpenStudy (anonymous):

derivative of a constant is 0... don't forget that!

OpenStudy (anonymous):

also, you had an error in taking another derivative... look it over and be careful!

OpenStudy (anonymous):

In any case, \[4-xy=y^3\] so you have the right idea, we do apply product rule, we get \[-y-x \frac{ dy }{ dx } = 3y^2 \frac{ dy }{ dx }\] right?

OpenStudy (arianna1453):

Right my mistake

OpenStudy (anonymous):

Simply solve for dy/dx now :)

OpenStudy (arianna1453):

so it would then give you -y = -x dy/dx + 3y^2 dy/dx = -y/-x+3y^2

OpenStudy (anonymous):

Careful with the signs

OpenStudy (anonymous):

\[-y = 3y^2\frac{ dy }{ dx }+x \frac{ dy }{ dx }\] right?

OpenStudy (arianna1453):

crap right

OpenStudy (arianna1453):

Wait are you sure.

OpenStudy (arianna1453):

I thought it would be adding x

OpenStudy (anonymous):

I'm not sure what you mean, can you please show it

OpenStudy (arianna1453):

at the very beginning its -(1)(y) + x dy/dx

OpenStudy (arianna1453):

Oh no no. Ignore me sorry got that wrong. Youre right. So then i got the answer of -y/x+3y^2

OpenStudy (anonymous):

Perfect! :)

OpenStudy (anonymous):

\[\frac{ dy }{ dx } = - \frac{ y }{ x+3y^2 }\]

OpenStudy (arianna1453):

Thank you!!! can you help me with another?

OpenStudy (anonymous):

Hey, sure I can try

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