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Mathematics 13 Online
OpenStudy (anonymous):

I need a little help here. I'm kinda stuck.

OpenStudy (anonymous):

OpenStudy (astrophysics):

Ok how did you get that

OpenStudy (anonymous):

I was using a calculator given to by my teacher to use, and somehow got confused in the process.

OpenStudy (astrophysics):

Ok, well what is the slope?

OpenStudy (anonymous):

6 over 7

OpenStudy (anonymous):

y= (y point2 - y point 1)/ (x point 2 - x point 1) multiplied by x + your y intercept value then rearrange to get y and x on the same side

OpenStudy (astrophysics):

Ok so, we get slope from using \[m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} } = \frac{ -1-2 }{ -3-1/2 } = \frac{ -3 }{ -7/2 } \implies \frac{ 6 }{ 7 }\] so that's good, now lets try to get it in equation of a line form (y=mx+b) and we'll work about the rest later, to get b that is the y - intercept (where the line crosses the y - axis)

OpenStudy (astrophysics):

worry*

OpenStudy (anonymous):

I need to find the y intercept now?

OpenStudy (anonymous):

If so, the y-intercept would be 11 over 7. Right?

OpenStudy (anonymous):

what is the y value when x is zero. that is the definition of the y-intercept value

OpenStudy (anonymous):

no

OpenStudy (astrophysics):

Yes, 11/7

OpenStudy (anonymous):

Okay so how would I find the standard form from there.

OpenStudy (anonymous):

sorry i was just eye balling, your answer is correct my mistake

OpenStudy (anonymous):

do you know how to move parts of equations to the other side of the equal sign?

OpenStudy (astrophysics):

Ok so we have \[y= \frac{ 6 }{ 7 }x+\frac{ 11 }{ 7 }\] correct?

OpenStudy (anonymous):

Yes correct

OpenStudy (anonymous):

And that is also the part were I get confused.

OpenStudy (astrophysics):

Lets start off by factoring out 1/7 so we get \[y= \frac{ 1 }{ 7 }(6x+11) \implies 7y = 6x+11\] so far so good?

OpenStudy (anonymous):

Yes

OpenStudy (astrophysics):

Can you finish it off

OpenStudy (anonymous):

I writing everything down so next time I won't forget

OpenStudy (anonymous):

Yes I can

OpenStudy (astrophysics):

Alright, just to make sure, what's next?

OpenStudy (anonymous):

is the next 6x-7y=-11?

OpenStudy (astrophysics):

All we have to do is subtract both sides by -6x

OpenStudy (astrophysics):

\[7y=6x+11 \implies 7y-6x=11\] right?

OpenStudy (astrophysics):

Now compare with your options

OpenStudy (anonymous):

So my option would be B?

OpenStudy (astrophysics):

No, \[7y-6x=11 \implies -6x+7y=11\]

OpenStudy (anonymous):

I'm sorry I was getting ready to correct myself, but yes it would be D

OpenStudy (astrophysics):

:)

OpenStudy (anonymous):

Thank you for the help :)

OpenStudy (astrophysics):

Yw

OpenStudy (anonymous):

the steps for standard form: 1) find the slope/m value: (y2-y1)/(x2-x1) 2) find the y intercept value: find b by plugging in a point this can be done by choosing a point, and plugging the y value in for y and the x value in for x to the equations y = mx + b which creates (y point) = (slope value)(x point) + b and then solve for b 3) use the y= (slope value)x + (y intercept value which is b value) and rearrange to have x and y on the same side. your equation should take on the form ax + by = c

OpenStudy (anonymous):

Thank you I would write that down as well just to be on the safe side.

OpenStudy (anonymous):

standard form is ax + by = c

OpenStudy (anonymous):

yeah and if you struggle watch youtube videos. theres plenty of math help even for 1st year univeristy students. try and predict the steps of the youtuber. its a great way to get the hang of a difficult math (or poorly taught) concept

OpenStudy (astrophysics):

Also another method, if you want equation of a line: First find the slope, using the following formula: \[m = \frac{ y_{2}-y _{1} }{ x _{2}-x _{1} }\] where your coordinates represent \[(x_1,y_1)~~\text{and}~~(x_2,y_2)\] Once you manage to get that, plug in m and your first coordinates in the point - slope form: \[y-y _{1}=m(x-x _{1})\] do some little algebra and eventually you will have slope - intercept form \[y=mx+b\] mhm yes all of these are sort of the same with different formula that give you equation of a line :)

OpenStudy (anonymous):

that is another great method as well!

OpenStudy (anonymous):

Thank you

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