Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

find x y and z GOLD MEDAL

OpenStudy (anonymous):

OpenStudy (anonymous):

I want mine in silver tho

OpenStudy (anonymous):

idk how to give silver medals

OpenStudy (anonymous):

There are only gold medals, that's why I'm always sad

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

do you know how to use sin and cos?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

This is much easier with 30-60-90 triangle rules and 45-45-90 triangle rules

OpenStudy (anonymous):

I get weird answers with those rules :(

OpenStudy (anonymous):

ok so were going to assume a=12 because algebra is easier than numbers lol. so to find z, we need the angle between a and z. do you know what that angle is?

OpenStudy (anonymous):

30 degrees

OpenStudy (anonymous):

\[\large \sf y\sqrt{3}=12\]\[\large \sf y=\frac{12}{\sqrt{3}}\] \[\large \sf z=2y\] Ez applications

OpenStudy (anonymous):

so z would be 2 times\[12\sqrt{3}\]

OpenStudy (anonymous):

Well \(\large \sf 2\frac{12}{\sqrt{3}}\)

OpenStudy (anonymous):

the easiest method would be z*cos30=a where z = a / cos30 = 12/ cos30 or z= a/sin60

OpenStudy (anonymous):

I'm so confused

OpenStudy (anonymous):

this based on the relationships with right triangles and the unit circle

OpenStudy (anonymous):

have you learned the unit circle yet?

OpenStudy (anonymous):

or trig cirle. forget what its called

OpenStudy (anonymous):

yes I have, but I barely understood it

OpenStudy (anonymous):

I just need x

OpenStudy (triciaal):

|dw:1451963722422:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!