Question

How do you calculate the total work required in this fluid problem?

Answer 1

If you don't mind me asking, what class is this in?

Answer 2

Calculus.

Answer 3

oh ok interesting!

Answer 4

What is the complete statement of the problem ?

Answer 5

A trough 15 meters long, whose cross section is a right isosceles triangle as shown, is partially filled with a liquid with a weight density of 6000 newtons per cubic meter. The depth of fluid in trough is 2 meters. Write a definite integral that expresses the work done in pumping all of the fluid out of the trough.

Answer 6

I know the form of the integral. What I'm having issue is with finding the volume of said fluid in trough as well as the work to lift the weight of representative rectangular solid a distance h.

Answer 7

\[\int\limits_{0}^{2} density \space (volume)(h)\] The question is...what volume and h am I looking for?

Answer 8

the volume = base * height /2 *length. sorry my mistake

Answer 9

I didn't see the integral

Answer 10

all good!

Answer 11

\[\int\limits_{0}^{2} 6000\frac{ 5 \sqrt2}{ 2 }(2x)(15)\]