Gibbs and Work
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That's not correct, is it? Here are a bunch of equations for reference:\[\rm dG = Vdp - SdT\]\[\Delta G = \Delta H - T \Delta S\]\[\Delta H = \Delta U + \Delta (PV) \]
What are we doing here? What's the question?
\(\sf \Delta G = [\Delta U + \Delta(PV)] - T\Delta S \)
hmm
@Zela101 We're trying to explain the fact that the change in Gibbs free energy is the maximum possible work of non-expansion that can be extracted by a system. (I still don't understand what that means though.)
The change in potential energy is defined as\[\Delta U = -w\]So these two terms are very related.
yes
\(\sf \Delta U = \Delta A+T\Delta S \) Helmholtz Free Energy \(\sf \Delta G = [\Delta U + \Delta(PV)] - T\Delta S \) \(\sf \Delta G = \Delta A + T\Delta S + \Delta(PV) - T\Delta S \rightarrow \Delta G = \Delta A + \Delta (PV)\)
hmmm that looked pretty in my mind, but not so in paper
\(\sf \Delta PV = \Delta G - \Delta A \)
What do you think, are we going anywhere?
Not quite sure. I don't know what Helmholtz free energy is apart from the definition, so it's going to be hard for me to relate
HAHA if we think of it as the energy within the system itself, then would that help us in terms of energy transfer?
I mean a non-expansion from that last line of equation I did would show a + G and whatever value of internal system A But here is what confuses me. I thought G is the system as well.
I thought I remember a schematic diagram a while back from hyper physics about this, let us look it up
HEY LOOK I found it http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/helmholtz.html
nice lol
brb mechanics is my first wife
what do you think, Zale? I think I was close. With the G = U -TS + PV
yeah, we did say something like this in the chat, like we're removing the heat which is being used to increase the entropy and nothing else http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/imgheat/gibb.gif
Combining Gibbs energy G = H-TS, and the enthalpy H = U +PV and getting G = U + PV -TS seems right. I agree nin.
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