Question

3^2x = 3^x-5

Answer 1

Help!

Answer 2

it really just your ordinary linear equation

Answer 3

You have to use log

Answer 4

\[\text{{if}~~a^n=a^m\]
then n=m

Answer 5

the only way right and left are equal is when the exponents are the same

Answer 6

meaning equal

Answer 7

It's suppose to equal -5 but I know know how

Answer 8

so 2x=x-5

Answer 9

yeah that's correct

Answer 10

How?

Answer 11

well you said something about logs
that's correct too, you take care of the base using the same log base both side
so you only get exponents left
so 2x=x-5
solve for x
2x-x=-5
x=-5

Answer 12

So the bases cancel out?

Answer 13

\[3^{2x}=3^x-5\]
put\[3^x=y\]
squaring
\[\left( 3^x \right)^2=y^2,3^{2x}=y^2\]
y^2-y+5=0
y=?

Answer 14

Thanks