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Mathematics 15 Online
OpenStudy (anonymous):

Help on dividing radicals

OpenStudy (anonymous):

\[\frac{ 4 }{ 5\sqrt{2} }\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

@23coffmank thats my question

OpenStudy (anonymous):

@hartnn @ParthKohli

hartnn (hartnn):

have you tried rationalizing the denominator? by multiplying numerator and denominator by \(\sqrt 2\)

OpenStudy (anonymous):

i get 20+4sqrt2/22 for some reason

hartnn (hartnn):

:O \(\Large \dfrac{4 \times \sqrt 2}{5 \sqrt 2 \times \sqrt 2} \) whats \(\sqrt 2 \times \sqrt 2 = ... ?\)

OpenStudy (anonymous):

and the denominator for my possible answers are 23 and 27

OpenStudy (anonymous):

the numerator is a negative in the possible answers.

OpenStudy (anonymous):

thats 2 right

hartnn (hartnn):

yes. and your "possible answers" are weird. Can you post the screenshot of the question along with options/possible answers?

hartnn (hartnn):

\(\Large \dfrac{4 \times \sqrt 2}{5 \sqrt 2 \times \sqrt 2} = \Large \dfrac{4 \times \sqrt 2}{5 \times 2} = \dfrac{2\sqrt 2}{5}\) thats it!

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

hartnn (hartnn):

no...not only options, question alongwith options...

OpenStudy (anonymous):

hartnn (hartnn):

ahh ... i think your denominator is \(5 - \sqrt 2\)

OpenStudy (anonymous):

the question says- Rationalize the denominator of (insert the equation first posted)

hartnn (hartnn):

or more possibly \(5+\sqrt 2\)

OpenStudy (anonymous):

it says +

hartnn (hartnn):

hmm...you should've posted your question accurately. anyways, rationalize the denominator by multiplying numerator and denominator by \(5-\sqrt 2\)

hartnn (hartnn):

how you got 22? \(5^2 -(\sqrt 2)^2 = 25-2 = 23\) in the denominator

hartnn (hartnn):

and since the numerator is \(4\times(5-\sqrt 2)\) it'll be \(20 - 4\sqrt 2\)

hartnn (hartnn):

ask if any doubts :)

OpenStudy (anonymous):

Thank you!!

hartnn (hartnn):

welcome ^_^

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