Question

What is the solution to the system of equations?
5x+4y=8
x-2y=10







( , )

Answer 1

will give medel

Answer 2

solve for x in the second equation first

Answer 3

ok x=2y+10

Answer 4

now plug 2y + 10 for x in the first equation

then solve for y

Answer 5

@Mehek14
@AloneS ???

Answer 6

oh ok

Answer 7

oh ok

Answer 8

wait how do i plug it in

Answer 9

instead of x in the first equation, you put 2y + 10

Answer 10

sorry really bad at math :/

Answer 11

The point here is to eliminate one variable, x or y. Your other helper is suggesting that you solve one of the equations for x and then subst. the result for x in the other equation.

Answer 12

Jiggly: can you solve x-2y=10 for x? It's already been done in this conversation.

Answer 13

ya its x=2y+10

Answer 14

do you want me to solve the first equation now

Answer 15

ye plug it in and solve for y

Answer 16

its x=−4/5y+8/5

Answer 17

no dont solve for x in the first equation

put 2y + 10 instead of x

Answer 18

sorry im really lost here

Answer 19

sorry im really lost here

Answer 20

Jiggly: You have solved the 2nd eq'n for x. Good. Now, use your result (a formula for x) to eliminate x from the first equation. This is not the same thing as solving the first equation for x.

Do you see x in the first equation? If so, enclose it in parentheses.
Next, throw out that x.
Next, where x was, write in 2y+10 (in other words, subst. 2y+10 for x)

Answer 21

Then the first eq'n will be an eq'n entirely in y (no x). Solve it for y.

Answer 22

oooh ok

Answer 23

so i replace the x in the first equation for 2y+10

Answer 24

y=3andx=4

Answer 25

right

Answer 26

-3 right

Answer 27

@Mehek14

Answer 28

ye (4,-3)

Answer 29

@jigglypuff87497840

Answer 30

thanks alot i really apreciate it

Answer 31

Jiggly: remember that you can check your own results yourself; you don't need our help for that. If you believe the solution is (4,-3), substitute 4 for x in either equation, and then -3 for y in that same equation. Is the resulting equation true or false?